H- has the noble gas config. of He(helium).
N3- has a electronic configuration of Ne(neon).
Ni2+ doesn't have the stable config. of any noble gas.It's config. is [Ar]4s23d10.
no, it is not
Ni(s) | Ni2+(aq) Ag+(aq) | Ag(s)
Ni2S3
(Ni2+)aq and (CrO42-)aq
Ni2- would be the correct answer. This would be highly unusual and not really make sense. Nickel has 28 protons and any ions would usually have 26 or 25 electrons and thus would be Ni2+ or Ni3+
no, it is not
if the donor consecration ( nd )is much larger than the intrinsic concentration( ni )then n0=nd when n0 is the thermal equilibrium concentration of free electron so : nopo=ni2 (when p0 is the thermal equilibrium concentration of holes ) po=ni2/nd do some basic math we got nd=ni2/po
Electron Arrangement for Nickel: 1s22s22p63s23p63d84s2 the electron orbital arrangement in terms of increasing energy however is 1s22s22p63s23p64s23d8. Using the "noble gas core" method the arrangement can also be written [Ar]3d84s2. The arrangement for Ni2+: 1s22s22p63s23p63d8
Ni2+ + 2Cl- also OH- + H+ from water
ni2 guan3
Ni(s) | Ni2+(aq) Ag+(aq) | Ag(s)
haixt ang hrap naman ni2^^
Ni2S3
Ni2+
Ni2(CrO4)3
Formula: Ni2(S2O8)3
ni2 hen3 huai4 the numbers are for phonetics