There is only one polar group that can be found in cholesterol despite it being nonpolar. That one group is a hydroxyl group.
Yes Yes
As you can see here this is the equation of acetic and stearic acid.it shows how they are different from each other. This is because acetic acid reacts much more exp[losively with water.
YES Cholesterol is an AlcoholThe polar hydroxyl group at the end of a cholesterol molecule is made of two atoms. These two molecules make cholesterol an alcohol. Ethanol, the alcoholic component of alcoholic beverages, has this same structure at the end of its molecule..,,,By: Farman marwat kpk, PAKISTANMSC CHEMISTRYGOMAL UNIVERSITY
Hexane is a non-polar chain hydrocarbon; on the principle of "like dissolves like" hexane will dissolve other non-polar compounds quite well. Water is a polar molecule, as are all halogens as exemplified by the simplest common halogen of all, hydrochloric acid. Halogen acids, common refrigerants, even some anesthetics are all polar molecules and therefore dissolve fairly well in other polar liquids, including water.
cholesterol
Methyl and hydroxyl groups
Lipid
steriod
yes as all of the OH groups make it polar
# Steroids # cholesterol # triglyceride
well im not 100% sure, but i know that water is polar, and only other polar things can dissolve into it. fats, i.e. cholesterol, are not soluble in water, and therefore must be nonpolar. ALSO, cholesterol is made up of four hydrocarbon rings. hydrocarbon rings, obviously, are made of hydrogen and carbon. (side note - polar compounds are formed when the difference of electromagnetivity - how much the element attracts electrons - between the elements causes an imbalance in the direction of attraction). the difference in electromagnetivity between those two elements is too little to be considered a polar molecule.
Blood Cholesterol levels are dependent on many factors of which antigen 'a' is one. Antigen 'a' is present only in blood groups A and AB. Hence, blood cholesterol levels are higher in individuals with blood groups A and AB.