The reaction is:
HBr + KOH = KBr + H2O
This is an acid/base reaction, so your products will be water and a salt. The products of this particular reaction are H2O (water) and KBr (potassium bromide, a salt.)
Potassium bromide (KBr) is formed
0.75 M
Balanced equation. KOH + HBr -> KBr + H2O everything is one to one, so... Molarity = moles of solute/liters of solution ( change ml to liters ) 0.25 M KOH = moles KOH/0.015 liters = 0.00375 moles of KOH this is as many moles that you have of HBr, so... Molarity of HBr = 0.00375 moles/0.012 liters = a concentration of HBr that is 0.31 M
KBr and some water H2O
They are all 1: KOH + HBr = KBr + H2O
NO!!! It is a neutralisation reaction. Reason it produces water (pH =7) KOH + HBr = KBr + H2O KBr (Potassium bromide) is a (chemical) salt. Remember the the empirical acid equations. Acid + Alkali = Salt + water Acid + Base = Salt + water Acid + metal = Salt + hydrogen Acid + carbonate = Salt + Water + Carbon dioxide. NB Acid formulas are always writen as 'HA'. Where 'A' is the anion. Alkali formulkas are always written as 'MOH'. Where 'M' is the metal cation. NNB Notice the positions of the 'H' in these formulas.
0.75 M
Balanced equation. KOH + HBr -> KBr + H2O everything is one to one, so... Molarity = moles of solute/liters of solution ( change ml to liters ) 0.25 M KOH = moles KOH/0.015 liters = 0.00375 moles of KOH this is as many moles that you have of HBr, so... Molarity of HBr = 0.00375 moles/0.012 liters = a concentration of HBr that is 0.31 M
KBr and some water H2O
They are all 1: KOH + HBr = KBr + H2O
NO!!! It is a neutralisation reaction. Reason it produces water (pH =7) KOH + HBr = KBr + H2O KBr (Potassium bromide) is a (chemical) salt. Remember the the empirical acid equations. Acid + Alkali = Salt + water Acid + Base = Salt + water Acid + metal = Salt + hydrogen Acid + carbonate = Salt + Water + Carbon dioxide. NB Acid formulas are always writen as 'HA'. Where 'A' is the anion. Alkali formulkas are always written as 'MOH'. Where 'M' is the metal cation. NNB Notice the positions of the 'H' in these formulas.
76.0*0.25=19 38.0*0.50=19 19-19=0 Cancel each other out ANSWER=7 just water and salt(not acid <7)(not basic >7)
M1V1=M2V210mLX0.121 = ? X 17mL=0.0708
KOH - potassium hydroxide or caustic potash and HCl hydrochloric Acid
CH3COOH + KOH = CH3COOK + H2O
KCl and water are formed.
It's a salt with a high pH.Strong acids Weak acidsWeak bases Strong bases HBr CH3COOH NH3 NaOH HCl HF NH4OH KOH H2SO4 HCN Cu(OH)2 Ca(OH)2
25 milliliters of the solution has . 037 moles of H2SO4. The neutralization reaction is H2SO4 + 2 KOH yields 2 H2O + K2SO4. So, . 074 moles of KOH are required. This equals 2. 71 mL of solution.