2 Al + 6 H2O > 2 Al(OH)3 + 3 H2
Al(OH)3 + NaOH > Na+ + [Al(OH)4]-
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6H2O(l)+2Al(s)+2NaOH(aq)--------------- 2NaAl(OH)4(aq)+3H2(g)
Normal word equation:
Aluminium (s) + sodium hydroxide (?) ----> aluminum hydroxide (aq) + sodium (s)
Normal equation:
Al + NaOH -----> AlOH + Na
Balanced equation:
Al + NaOH ------> AlOH + Na
A small quantity of aqueous sodium hydroxide forms white gelatinous precipitate of Aluminium hydroxide which on reacting with excess sodium hydroxide forms a soluble salt Sodium aluminate.
AlCl3 + 3NaOH = Al(OH)3 + 3NaCl
Al(OH)3 + NaOH = NaAlO2 + 2H2O
aluminium hydroxide (aqueous) and if there is excess sodium hydroxide, sodium aluminate is formed as aluminum is an amphoteric metal.
Although it wouldn't actually react, the only possible products are sodium and aluminium hydroxide.
If the sodium hydroxide is in concentrated solution in water, the most likely reaction is
2 Al (s) + 2 NaOH (aq) + 2 H2O = 2 NaAlO2 (aq) + 3 H2 (g).
Al2O3 + 6NaOH --> 2Al(OH)3 + 3Na2O
As you can see, when aluminium oxide reacts with sodium hydroxide, aluminium hydroxide and sodium oxide are produced.
2Al + 2NaOH + 6H2O → 2NaAl(OH)4 + 3H2
yes it does
Calcium hydroxide, a base, will reaction with phenol, a weak acid in a neutralization reaction to give a salt (calcium phenoxide (Ca(PhO-)2) and water.
There is no reaction, therefore no equation!!
The chemical reaction is:NH4ClO4 + KOH ↔ KClO4 + NH4OH
We see the chemical reaction but we write the chemical equation.
2Na+2H20->2Na0H+H2 ::::apex
Aluminium hydroxide could be formed
Dissolving is not a chemical reaction; any chemical equation.
C6H13Na + H2O
A double displacement chemical reaction happens generating Aluminium Hydroxide and Phosphine gas
Any reaction occur.
The balanced chemical equation is: MgO + H2O → Mg(OH)2 The product formed in this reaction is magnesium hydroxide.
Simplified. 2NaOH + H2SO4 -> Na2SO4 + 2H2O
Calcium hydroxide, a base, will reaction with phenol, a weak acid in a neutralization reaction to give a salt (calcium phenoxide (Ca(PhO-)2) and water.
There is no reaction, therefore no equation!!
2 NaOH + SO2 = H2O + Na2SO3
2Al + 3CuCl2 --> 3Cu + 2AlCl3
The reaction is the following: H2SO4 + 2NaOH = Na2SO4 + 2H2O