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How many bits are in the subnet ID block and What are the values of these bits for a link-local IP address?
16 bits per block
How many bits are in the Subnet ID blocks and what are the values of these bits for a link-local IP address?
16 bits per block
What is the size of address bus in 8086?
The address bus in the 8085 is 16 bits wide.
How many bits does a Java char contain?
16 bits. Java char values (and Java String values) use Unicode.
How many different values can be stored in 16 bits?
65,536
How many bits define a hardware address?
There are 16 bits in a port address, which gives a port range of 0 - 65535
How many network and host bits are in a slash 16 network?
Assuming IP version 4 (the current standard), a complete IP address has 32 bits. /16 means that the first 16 bits specify the network; the remaining bits (also 16 in this case - calculated as 32 minus 16) specify the host.Assuming IP version 4 (the current standard), a complete IP address has 32 bits. /16 means that the first 16 bits specify the network; the remaining bits (also 16 in this case - calculated as 32 minus 16) specify the host.Assuming IP version 4 (the current standard), a complete IP address has 32 bits. /16 means that the first 16 bits specify the network; the remaining bits (also 16 in this case - calculated as 32 minus 16) specify the host.Assuming IP version 4 (the current standard), a complete IP address has 32 bits. /16 means that the first 16 bits specify the network; the remaining bits (also 16 in this case - calculated as 32 minus 16) specify the host.
Size of 8086 address bus?
The 8086/8088 has an internal 20-bit address bus and 16-bit data bus. Externally, the address bus is 20-bits, and the data bus is 16-bits for the 8086 and 8-bits for the 8088.The data bus in the 8086 is 16 bits in size, while the address bus is 20.
How many address bits does 8085 have?
The 8085 has a 16 bit address bus.
If a binary number needs to represent 16 different values how long must the number be in bits?
4 bits
How many bits are needed in order to represent the decimal values from 0 to 15?
4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.4 bits. 24 = 16, so you have 16 different combinations.
What is the minimum number of bits would you need to represent 9 different values?
4.1 bit for 2,2 bits for 4,3 bits for 8,4 bits for 16.
