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Assuming IP version 4 (the current standard), a complete IP address has 32 bits. /16 means that the first 16 bits specify the network; the remaining bits (also 16 in this case - calculated as 32 minus 16) specify the host.
Assuming IP version 4 (the current standard), a complete IP address has 32 bits. /16 means that the first 16 bits specify the network; the remaining bits (also 16 in this case - calculated as 32 minus 16) specify the host.
Assuming IP version 4 (the current standard), a complete IP address has 32 bits. /16 means that the first 16 bits specify the network; the remaining bits (also 16 in this case - calculated as 32 minus 16) specify the host.
Assuming IP version 4 (the current standard), a complete IP address has 32 bits. /16 means that the first 16 bits specify the network; the remaining bits (also 16 in this case - calculated as 32 minus 16) specify the host.
Wiki User
∙ 14y ago
Wiki User
∙ 14y agoAssuming IP version 4 (the current standard), a complete IP address has 32 bits. /16 means that the first 16 bits specify the network; the remaining bits (also 16 in this case - calculated as 32 minus 16) specify the host.
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How many ip's in slash 24 network?
A slash 19 network includes 8,190 host per network. Prefix networks can are not arranged up to /31 since it would 0 host per network.
How do you know how many bits represent the network portion and the host portion?
When we express an IPv4 network address, we add a prefix length to the network address. The prefix length is the number of bits in the address that gives us the network portion. For example, in 172.16.4.0 /24, the /24 is the prefix length - it tells us that the first 24 bits are the network address. This leaves the remaining 8 bits, the last octet, as the host portion.
How many bits must be reallocated from the host ID to network ID to create sixteen sub-nets?
4
How many hosts and host bits are possible if you have an IP of 172.30.1.33 with a network mask of 255.255.0.0?
number of hots bits is 16 number of hosts 65 534
How many networks are there in a class c network?
Class C (192-223) In Class C there is 3 network bits and one host bit.
How many hosts can each class b network have?
16 384 networks are available in Class B network.
If you borrow 10 host bits from a Class B network address how many usable hosts are left?
62 hosts.
How many host bits in an IP address of 192.168.254.192?
IPv4 has 32-bits classified into 4 bytes out of which each byte is divided into network or hosts. Thus, it can have any combination like 1 host, 3 networks or 2 host, 2networks etc.
How many network and host bits are available for class C IP address?
By default Class C subnet mask is 255.255.255.0 = 24 bits for network id and 8 bits for host id. in Binary 1111 1111. 1111 1111. 1111 1111. 0000 0000 Here all 1s are Network bits and all 0s are host bits. For this subnet mask you can have 256 hosts. And you can use 254 host and asign IP address to them. By Saurabh
How many host address are there for an address with 21 bits for the network address?
2046 Breakdown: 11111111.11111111.11111000.00000000 /21 - 21 bits in network address represented by ones in binary address above. Leaves 2^11th power host addresses left (the zeros to the right). Equals 2048 host addresses minus the two reserved addresses = 2046
How many subnets and hosts per subnet can you get from the network 172.16.0.0?
There are 16 bits available; it is up to you how many of those bits you reserve for the subnet, and how many for the individual hosts within each subnet.
How many subnets can you have in a class C network with a 26 bit mask?
A Class C IP address has 24 bits for network and 8 bits for host. So to have a subnet mask of 26 bits, you will need to use 2 bits from host part.Number of subnets is given by the formula : 2^(no. of bits used from host part).Hence number of subnets in this case would be = 2^2 = 4.For e.g. if the class C IP address is 200.168.210.0the 4 subnet addresses would be :11001000.10101000.11010010.00000000 = 200.168.210.011001000.10101000.11010010.01000000 = 200.168.210.6411001000.10101000.11010010.10000000 = 200.168.210.12811001000.10101000.11010010.11000000 = 200.168.210.192Note: The digits in bold are the mask bits.
