The reason electricity is trsnsmitted at very high voltage is to reduce energy loss. As Power = V x I and heat loss = I2 R. Thus if I the current is low the energy lost in the transmission cables will be minimal. The reason electricity is trsnsmitted at very high voltage is to reduce energy loss. As Power = V x I and heat loss = I2 R. Thus if I the current is low the energy lost in the transmission cables will be minimal.
With 2000000 watts, 2000 kW or 2 megawatts you can provide power to many homes.
You multiply the power by time, ie kW*h
AnswerKiloWatt hours. Its a measure of energy use. It is the amount of power used over time.Energy is the ability to do work, while power is the rate at which work is done.Your water heater may have a power rating of 5 kW. If it runs for 8 hours in a day, you would use 40 kWh of energy doing the work of heating the water.
where, prices vary from region and power company get hold of a power bill The question should be: How much does 1.6 kWh cost. A kW is a measurement for power. The energy bill will increase if you sustain this power for a longer period (hence the h after kW, for hour).
kw of 100kva=100*0.8 pf=80kw( if the power factor is 0.8)
1 hp = 0.7457 kW Therefore by dividing 1 by 0.7457 we get 1 kW = 1.341 hp Just multiply either equation by the desired amount to find the equivalent power output. Either Imperial or metric
The question cannot be answered. It would depend on what device you are using to do the converting. [edit] Well, in the simplest terms: Power (kW) = Power (HP) x 0.7457 Power (HP) = Power (kW) x 1.341
Energy bill must be in terms of Energy unit (KWH) only. Energy is KW (power) utilized over a period of time. The unit of energy is Kilowatthour (KWH) Unit of power is Kilowatt (KW) KW is instantaneous power being utilized. KW (power) over a time period is Energy (KW H)
KVA=KW*Power factor, considering PF 0.9, 6KVA=KW*0.9 KW=6/.9=6.67
condenser capacity(kw) = compressor cooling capacity (kw) + compressor input (kw) power condenser capacity(kw) = Pf + Pa
kVA = kW divided by (power factor). The power factor is the cosine of the angle between voltage and current.
You can measure the output power of the motor (mechanical power or shaft power) by a speed and torque sensor. The product of speed (angular velocity to be precise) and torque is power. Is this case the output power. The SI unit of power is W, kW is 1000 W. So the power/1000=power [kW].
power factor means kw/kva
power factor means kw/kva
1 MW is 1000 kW therefore 10 MW is equal to 10,000 kW.
You multiply the power by time, ie kW*h
The correct symbol is 'kW', and it stands for 'kilowatt' which is the SI unit of power.
Your question cannot be answered, unless the power factor of the load is specified. Since true power(measured in watts) is the product of apparent power(measured in volt amperes) and the power factor of the load.So, given your figure of an apparent power of 20 kV.A(not 'kva'*), the corresponding value of true power could (theoretically!) range from20 kW at a power factor of 1.0, to0 kW at a power factor of 0.(*The correct symbol for kilovolt ampere is 'kV.A', not 'kva', and the correct symbol for kilowatt is 'kW', not 'kw'.)