Because heat rises. That means the top of the flame would br holding 99% of the heat. That is why the tip is hotter than other areas og the flame.
Take for example with the bunsen burner those who science at school it is because the heat gets hotter that it changes colour Now if you quickly waved your hand through the orange flame you would be absolutely fine but if you did it through the blue flame you would get serious burns.
Mass spectrometer would work.
blue flame
You would have to close the collar instead of opening it. This will produce a yellow flame. But it is not suitable for heating. Only a blue flame is suitable for heating as it is much hotter than a yellow flame. M.F. - The yellow smoky flame is the lack of Oxygen (O2) mixing with the Hydrocarbon methane (CH4)
The flame color would be green.
It usually produces a green sort of colour unless you hold the experiment out incorrectly
If you think to flame test the color is the same; the important factor is sodium with his spectral lines.
Ionic compounds occur between atoms of a metal and a non-metal therefore: CO2 would not, SrCl2 would, H2S would not and SO2 would not. Only SrCl2 would be an ionic compound.
If you are talking about a neon light, you can use any of the noble gases in a light. Helium would produce a pink color, neon would produce a red color, argon would produce a light blue color, krypton would produce a white color, xenon would produce a purple color. I don't recommend using radon, but if you were to it would produce a green color.
Sr2+ would be the cation and 2 Cl- would be the anions.
A: If you put a piece of copper wire on any type of flame (most preferably cooking flames), then you would observe that they produce a green color in the flame. Sometimes, it might give youa blue tinge but if it doesn't, it doesn't mean that there's something wrong with the copper you're using.
No, the flame needs the oxygen to burn. Without oxygen, the flame would go out.
There would be electron transitions in sodium atoms while the flame test. The majority of them would emit photons which would have same energy and frequency corresponding to yellow color.
you would produce radon gas.
If the test agent have free ions the ionization of the flame will be significant. When the energy reaches a point when it take more energy the flame ionization will not be significant.
The flame will turn a violet color. It will not explode.