About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
Yes, during process of osmoses the solvent from higher concentration to lower concentration moves through semipermeable membrane, the 2% solution has lower concentration of solute therefore higher concentration of solvent.
Basically there are many tests which is usually practiced to distinguish saturated Organic compounds from the unsaturated ones. But two of them are the most common: 1. Bromine water test. 2. Bayer's test. Basically Bromine water is red in color, so when an unsaturated compound (Alkene or Alkyne) is treated with it. The Bromine water get decolourized, on the other side the color is not changed when treated with saturated compound. In the Bayer's test KMnO4 solution is used, the unsaturated compound vanish its pink color while the saturated compounds do not.
(x L)((12%) = (100 L)(2%)x = 16.7 liters
Three. 35, 80, 112. The liquid status of 112 is still not certain. Two for sure, mercury and bromine.
A 3 percent solution is 1.5 times as strong as a 2 percent solution.
2%
The chemical equation is:C2H2 + 2 Br2 = C2Br2H4
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
hypotonic
About 80ml of water must be added to 40ml of a 25 percent by weight solution to make a 2 percent by weight solution.
hypertonic
Yes, during process of osmoses the solvent from higher concentration to lower concentration moves through semipermeable membrane, the 2% solution has lower concentration of solute therefore higher concentration of solvent.
A. 16 of 18 percent and 2 of 9 percent b. 14 of 18 percent and 4 of 9 percent c. 16 of 9 percent and 2 of 18 percent d. 14 of 9 percent and 4 of 18 percent
Basically there are many tests which is usually practiced to distinguish saturated Organic compounds from the unsaturated ones. But two of them are the most common: 1. Bromine water test. 2. Bayer's test. Basically Bromine water is red in color, so when an unsaturated compound (Alkene or Alkyne) is treated with it. The Bromine water get decolourized, on the other side the color is not changed when treated with saturated compound. In the Bayer's test KMnO4 solution is used, the unsaturated compound vanish its pink color while the saturated compounds do not.
Twice Half as strong. Really? What the heck kind of question is this?
1,2 dibromoethane and 1-bromo, 2-chloro ethane and 2-bromo ethanol