3 pi bonds C6H8 has a double and a triple bond in it's Lewis structure - the double bond contains 1 sigma and one pi bond while the triple bond has i sigma and 2 pi bonds
Benzene has covalent bonds. Each of the six carbons in benzene is sp2 hybridized meaning the ring has both sigma bonds and pi bonds. Benzene is aromatic meaning its pi electrons are delocalized and form a pi system.
Covalent
yes
C2H2 is a carbon bond. This particular type of carbon bond is referred to as a triple bond, as it contains two pi bonds and a sigma bond.
double bond contains one sigma bond and one pi bond triple bond contains one sigma bond and two pi bond
What are lacalized bond
3 pi bonds C6H8 has a double and a triple bond in it's Lewis structure - the double bond contains 1 sigma and one pi bond while the triple bond has i sigma and 2 pi bonds
Benzene has covalent bonds. Each of the six carbons in benzene is sp2 hybridized meaning the ring has both sigma bonds and pi bonds. Benzene is aromatic meaning its pi electrons are delocalized and form a pi system.
Covalent
yes
C2H2 is a carbon bond. This particular type of carbon bond is referred to as a triple bond, as it contains two pi bonds and a sigma bond.
You can think of pi bonds in the terms of pi electrons as well which will become more important in terms of aromaticity. A Triple bond has 1 sigma bond & 2 pi bonds. There are 6 electrons in a triple bond; 2 sigma electrons and 4 pi electrons. The two unhybridized p orbitals on each atom on either side of the triple bond are perpendicular to each other. So, if you are trying to determine the number of pi electrons in an aromatic monocyclic compound and you have an uninterrupted combination of sp & sp2 orbitals (sp3 does not have p orbitals), whenever you come across a triple bond you would add 4 pi electrons and for a double bond you would add 2 pi electrons. The important thing to remember though is if the question asks for the number of electrons delocalized in the ring because of the aforementioned p orbitals in a triple bond being perpendicular only 2 of the 4 available pi electrons would delocalize in the ring. The really dirty trick is that Huckel's rule applies to electrons in the cloud, delocalized electrons.
metallic bond
The aldehyde group -CHO contains 1 sigma bond ( C-H), 1sigma bond (C-O) 1 pi bond (C-O). And there is also another sigma bond attaching it to the rest of the molecule.
KMnO4 will add across the double bond of alkenes (or alkynes) resulting in the docolouring of KMnO4 but not an alkane such as ethane.
No, in aromatic compounds and some aliphatic compounds have deloclized pi bonds but in most of the alkenes and alkynes there are localized pi bonds.