These substances are in solution.
(aq) is from aqueous, a substance in solution.
hgrjhnyjhjdgjgjgchgg
HCN(aq) ==> H^+(aq) + CN^-(aq)Ka = [H+][CN-]/[HCN] and the value can be looked up in a book or on line.
'aq' , sometimes subscripted at the right of the element's symbol: eg. Na+aq
Barium chloride and sodium sulfate Molecular equation: BaCl2(aq) + Na2SO4(aq)--> BaSO4(s) + 2NaCl(aq) ionic equation: Ba+2(aq) + 2Cl-(aq) + 2Na+(aq) + SO4-2(aq) --> BaSO4(s) + 2Na+(aq) + 2Cl-(aq) Net ionic equation is Ba+2(aq) + SO4-2(aq) --> BaSO4(s)
They are all dissolved in water.
If you mean pure substances then:HCl(aq) and NaCl(aq) are not pure substances but solutions. The (aq) means the substance is dissolved in water.HCl(g) and NaCl(s) is are pure substances
(aq) is from aqueous, a substance in solution.
KOH (aq) + HCl (aq) = KCl (aq) + H20 so potassium chloride and water - KCl solution
AgNo3 (aq) + HCl (Aq) -> HNO3 (aq) + AgCl (s) there's no gass given off, only solid and aquous substances.
Made of just one substances
cleaners which is solvent
Carbonic Acid
1)Write the BALANCED equation for the reaction with CORRECT state symbols: Mg(s) +2HCl(aq)---------->MgCl2(aq) +H2(g) 2)Now rewrite the equation replacing aqueous substances as they would appear in solution( ie)as ions.Leave everything else as is in the standard state. Mg(s) + 2H+ (aq) + 2Cl-(aq)---->Mg2+(aq) +2Cl-(aq) +H2(g) 3)Now cancel ions common to both sides ,that is,spectator ions. Cancel the 2Cl-(aq) on each side. 4)Rewrite the equation without what you have canceled. Mg(s) + 2H+(aq)------>Mg2+(aq) + H2(g). Good Luck.
Ionisation in solution is not a chemical reaction. It can be written as one but still it's NOT: only physical change of state ( subscripted between brackets (s) or (aq) ) Na2S(s) --> 2Na+(aq) + S2-(aq)
The international dangerous goods regulations do not harmonize substances, they harmonize the regulations on how substances that meed the definition of dangerous goods will be packaged, marked, labeled, documented, and transported.
NaH2PO4(aq) + H2OàH3PO4(aq) + NaOH(aq) H3PO4(aq)ßàH+(aq) + H2PO4_(aq) H2PO4-(aq)ßàH+(aq) + HPO42-(aq) HPO42-(aq)ßàH+(aq) + PO43-(aq)