MnCl2 + NH3
16,45 g nitrogen are needed.
false two or more reactants react together to form products
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
394.794 grams
reversible reaction
oxidation number of Mncl2 is +2
36.41% = .3641 g of H2O 63.59% = .6359 g of MnCl2 .6359g MnCl2 x (1molm MnCl2/125.84g MnCl2)=.0051 mol MnCl2 .3641g H2O x (1 mol H2O/ 18.02g H2O) = .0202 mol H2O .0051 mol MnCl2 / .0051 = 1mol MnCl2 .0202 mol H2O /.0051 = 3.96 = 4 mol H2O Formula is: MnCl2 4H2O Manganese (II) chloride tetrahydrate
Reading this as what are the elements that make up Ammonia they are: Hydrogen Nitrogen Formula: NH3
Ammonia (NH3) is composed from nitrogen (N) and hydrogen (H).
Reactants. Reactants react to produce products.
The percent composition of manganese dichoride (MnCl2) is: - Mn: 44 % - Cl: 56 %
It will if it reacts with a strong enough base.
The reaction will produce ammonium chloride, NH4Cl.
16,45 g nitrogen are needed.
The name for MnCl2 is manganese (II) chloride. The compound is a pink polymeric solid that is non-corrosive and non-flammable.
The reactants are the substances that are doing the reacting to produce the result. (The substances on the left side of the equation are the reactants) So ZnS & O2 are the reactants.
NH3 + HCl ----> NH4Cl