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What do you get when you burn ch4 in the presence of o2?
It is a combusion.Water and CO2 is produced
When 3.05 of ch4 is mixed with 5.03 moles of o2 the limiting reactants is?
The balanced chemical equation for the reaction between CH4 and O2 is as follows: CH4 + 2O2 -> CO2 + 2H2O By comparing the moles of CH4 and O2 given, you can see that O2 is the limiting reactant because it will be completely consumed before all of the CH4 can react.
How do you balance the equation for CH4 O2 yield CO2 H2O?
The balanced chemical equation for the reaction CH4 + 2O2 → CO2 + 2H2O shows that 1 molecule of CH4 reacts with 2 molecules of O2 to produce 1 molecule of CO2 and 2 molecules of H2O. This equation ensures that the number of atoms of each element is the same on both sides of the reaction arrow.
What mass of oxygen is required to completely react with 20 grams of CH4?
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
CH4 plus O2 equals H20 plus?
The chemical reaction is: CH4 + 2O2 --> 2H2O + CO2 CO2 is the carbon dioxide.
What do you get when you burn ch4 in the presence of o2?
It is a combusion.Water and CO2 is produced
How many molecules of O2 ar needed in the chemical formula for burning methane?
You should set up a balanced equation for the combustion of CH4 first: CH4 + 2 O2 --> CO2 + 2 H2O Now you see that for every 1 mole of CH4 you have 2 moles of O2. Therefore if you have 2.67 L of CH4, you'll have 5.34 L of O2. You can also assume it's at STP just to check, since it all cancels out in the end: 2.67L CH4 (1mol CH4/22.4L)(2mol O2/ 1 mol CH4)(22.4L/1mol O2)= 5.34L O2.
24g of CH4 react with 96 g of O2?
The balanced chemical equation for the reaction is: CH4 + 2O2 -> CO2 + 2H2O Using the molar masses of CH4 and O2, we can calculate the moles present in 24g of CH4 and 96g of O2. From there, we can determine the limiting reactant and the amount of product formed.
When 3.05 of ch4 is mixed with 5.03 moles of o2 the limiting reactants is?
The balanced chemical equation for the reaction between CH4 and O2 is as follows: CH4 + 2O2 -> CO2 + 2H2O By comparing the moles of CH4 and O2 given, you can see that O2 is the limiting reactant because it will be completely consumed before all of the CH4 can react.
What is the balanced equation of CH4 plus O2 arrow CO2H2O?
The balanced equation is: CH4 + 2 O2 → CO2 + 2 H2O
If 2.8 moles of CH4 react with 3 moles of O2 what is the limiting reagent?
To determine the limiting reagent, we need to compare the amount of each reactant to their stoichiometric coefficients in the balanced equation. The balanced equation for the combustion of CH4 with O2 is: CH4 + 2O2 -> CO2 + 2H2O. From the given amounts, we can see that O2 is in excess, so CH4 is the limiting reagent.
When 85.0 g of CH4 are mixed with 160 g of O2 the limiting reactant is?
When 85.0 g of CH4 are mixed with 160. g of O2 the limiting reactant is __________. CH4 + 2O2 → CO2 + 2H2O
How do you balance the equation for CH4 O2 yield CO2 H2O?
The balanced chemical equation for the reaction CH4 + 2O2 → CO2 + 2H2O shows that 1 molecule of CH4 reacts with 2 molecules of O2 to produce 1 molecule of CO2 and 2 molecules of H2O. This equation ensures that the number of atoms of each element is the same on both sides of the reaction arrow.
What is the balanced equation for methane burns oxygen to form water and carbon diooxide?
Unbalanced CH4 + O2 = H2O + CO2 Balanced CH4 + 2O2 = 2H20 + CO2
What mass of oxygen is required to completely react with 20 grams of CH4?
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
When 85.0 g of CH4 are mixed with 160 g of O2 what is the maximum amount of CO2 that can be produced?
The balanced chemical equation for the reaction of CH4 and O2 to produce CO2 is: CH4 + 2O2 -> CO2 + 2H2O First, calculate the limiting reactant by converting the given masses of CH4 and O2 to moles. Then, use the stoichiometry of the reaction to determine the maximum amount of CO2 that can be produced, based on the limiting reactant.
CH4 plus O2 equals H20 plus?
The chemical reaction is: CH4 + 2O2 --> 2H2O + CO2 CO2 is the carbon dioxide.
