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What information would be requierd to determine the mass number of nitrogen?
You would need to know how many protons and neutrons are in the nucleus of a particular isotope of nitrogen. The number of protons, which is its atomic number, will always be the same, no matter which isotope is given, but the number of neutrons differs with different isotopes. For example, one isotope of nitrogen has 7 neutrons. To determine its mass number, find nitrogen on the periodic table, and you will see that its atomic number is 7. So this isotope of nitrogen has 7 protons. Now, add the 7 neutrons to the 7 protons, and you get a mass number of 14 for this isotope of nitrogen, which is called nitrogen-14. (Isotopes are named by their mass numbers.) Another isotope of nitrogen has 8 neutrons. Add the 8 neutrons to the 7 protons (atomic number), and you get a mass number of 15 for this isotope of nitrogen, called nitrogen-15.
How many nitrogen molecules are in 12.88g of nitrogen gas?
To determine the number of nitrogen molecules in 12.88g of nitrogen gas, you first need to convert grams to moles using the molar mass of nitrogen (28.02 g/mol). Then, you can use Avogadro's number (6.022 x 10^23) to find the number of molecules in that number of moles.
How many m3 nitrogen in 1 kilogram?
To answer this you need to find out the mass of 1m (or 1 dm) of nitrogen.
Which information would be required to determine the mass number of nitrogen?
To determine the mass number of nitrogen, you would need to know the number of protons and neutrons in its nucleus. Nitrogen has 7 protons, so the mass number can be calculated by adding the number of protons (7) to the number of neutrons in the nucleus.
Determine the mass of 21 mol N?
To determine the mass of 21 mol of nitrogen (N), you need to know the molar mass of nitrogen, which is approximately 14.01 g/mol. Mass = Number of moles * Molar mass Mass = 21 mol * 14.01 g/mol = 294.21 g Therefore, the mass of 21 mol of nitrogen is approximately 294.21 grams.
How many moles of nitrogen are contained in a 35.0g sample?
To find the number of moles of nitrogen in a 35.0g sample, you need to divide the mass of the sample by the molar mass of nitrogen. The molar mass of nitrogen is approximately 14.01 g/mol. Therefore, 35.0g / 14.01 g/mol = approximately 2.5 moles of nitrogen.
How many moles of nitrogen in 42 grams of nitrogen?
As a rule of thumb, the atomic mass of an element equals the number of grams of that element equals a mole. Since the atomic mass of Nitrogen is 14, there are 14 grams in one mole of Nitrogen. Next, we just have to divide 42 by 14 and we get our answer: There are 2.9988 moles in 42 grams of Nitrogen.
How many moles are in 6.64 grams of nitrogen monoxide?
For this you need the atomic (molecular) mass of NO. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NO=30.0 grams6.64 grams NO / (30.0 grams)= .221 moles NO
How many moles are there in 10.0 of nitrogen dioxide?
To find the number of moles in 10.0 g of nitrogen dioxide (NO2), you first need to find the molar mass of NO2, which is approximately 46.01 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 10.0 g / 46.01 g/mol ≈ 0.22 moles of nitrogen dioxide.
How many molecules are in 67.9 g N?
To find the number of molecules in 67.9 g of nitrogen (N), you first need to convert the mass (in grams) to moles using the molar mass of nitrogen (28.02 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules.
What is the mass percent of nitrogen in NF3?
To find the mass percent of nitrogen in NF3, you need to calculate the molar mass of NF3 and then determine the mass of nitrogen in one mole of NF3. The molar mass of NF3 is 71.001 g/mol. The molar mass of nitrogen in NF3 is 14.007 g/mol. Therefore, the mass percent of nitrogen in NF3 is (14.007 g/mol / 71.001 g/mol) * 100% ≈ 19.76%.
What mass of oxygen contain same number of molecule as 42g of nitrogen?
Both nitrogen and oxygen exist at standard temperature and pressure as diatomic molecules. Therefore, the relative masses of equal numbers of molecules of the substance will the same as the ratios of their atomic masses, which are 15.9994 for oxygen and 14.0067 for nitrogen. The mass of oxygen that contains the same number of molecules as 42 g of nitrogen is 42(15.9994/14.0067) or 48 g, to the justified number of significant digits.
