number of moles = mass/molar mass
mass = number of moles x molar mass
21mol x 14gmol-1 = 294g
molar mass of Nitrogen is 14, which you can find on a periodic table
That depends. In a solution used for silver staining in biochemical research, for example, silver nitrate is at 0.8%, sodium hydroxide at 1.9% and ammonium hydroxide at 1.4%, with the rest made up of sterile deionized water.
[ 217(g) / 44.013(g/mol) ] * 2(molN/molN2O) = 9.86 mol NDivide mass (g) by molar mass (g/mol) to get moles of N2O, this should be multiplied by 2 for the stoechiometric factor of atoms N per molecule N2O.
Nitrogen has an average atomic mass of about 14 while hydrogen has an average atomic mass of about 1, so the total molecular mass of NH3 is about 17. From this we find that the mass percentage of N in NH3 is about 14/17 = 82%. To get more precise numbers, look up the exact atomic masses from a periodic table.
The molecular weight(M) of chalk(CaCO3) = (40+12+48)g/mol =100g/mol and teaspoon (m)= 4.93g We know, n=m/M So, n= (4.93/100) mol = .0493 mol To find out number of molecules we use, N= n x NA equation. N= .0493 mol x 6.02 x 1023 molecules/mol =2.968 x 1022 molecules Therefore, there are 2.968 x 1022 molecules in a teaspoon of chalk.
The molar mass of nitric acid (HNO3) is approximately 63 g/mol. Nitric acid contains one nitrogen atom, which has a molar mass of about 14 g/mol. This means that the percentage by mass of nitrogen in nitric acid is approximately 22%.
3.55g
The molar mass of N is 14 g/mol and NH₃ is 17 g/mol. To find the maximum mass of NH₃ from 1000g of N, first convert 1000g N to moles (1000g / 14 g/mol = 71.43 mol). Then, use the molar ratio of N to NH₃ (1:1) to determine the maximum mass of NH₃ that can be produced (71.43 mol * 17 g/mol = 1214.71g).
1 mol Na X (22.99 Na / mol Na) = 22.99 g Na1 mol N X (14.01 g N / mol N) = 14.01 g N3 mol O X (16.00 g O / mol O) = 48.00 g OMolar mass of NaNO3 = 85.00 g/mol
Molecular mass = sum of all atoms masses = 1(molN/mol NH3)*14.01(g/mol N) + 3(molH/mol NH3)*1.008(g/mol H) = 17.03 g/mol NH3
To find the mass in grams of 8.2 × 10²² molecules of N₂i₆, we first need to determine the molar mass of N₂i₆. Assuming N₂i₆ refers to a compound of nitrogen (N) and iodine (I), we would calculate its molar mass based on the atomic weights of nitrogen (approximately 14 g/mol) and iodine (approximately 127 g/mol). Once we have the molar mass, we can convert the number of molecules to moles using Avogadro's number (6.022 × 10²³ molecules/mol) and then multiply by the molar mass to find the mass in grams. Without the exact formula or molar mass, the exact mass cannot be calculated here.
The formula for ammonium bicarbonate is NH4HCO3. To find the mass percent of nitrogen (N), calculate the molar mass of nitrogen in the formula and divide it by the molar mass of the entire compound NH4HCO3. The molar mass of N is 14.01 g/mol, and the molar mass of NH4HCO3 is 79.06 g/mol. Therefore, the mass percent of nitrogen in ammonium bicarbonate is (14.01 g/mol / 79.06 g/mol) * 100% = 17.7%.
[ 217(g) / 44.013(g/mol) ] * 2(molN/molN2O) = 9.86 mol NDivide mass (g) by molar mass (g/mol) to get moles of N2O, this should be multiplied by 2 for the stoechiometric factor of atoms N per molecule N2O.
That depends. In a solution used for silver staining in biochemical research, for example, silver nitrate is at 0.8%, sodium hydroxide at 1.9% and ammonium hydroxide at 1.4%, with the rest made up of sterile deionized water.
To find the mole of a chemical from the given mass, use the formula mass = moles x molar mass or m = nM so to find the n... isolate the n first in the formula. n = m/M. The M signfies the Molar Mass of Hydrogen which is 1.008 g/mol and the m signifies the given mass of hydrogen which is 2.002 g. Divide 2.002 g by 1.008 g/mol which is 1.986 mol of H. Remember ... look at the units. In the formula, if you isolate M... M = m/n Since the unit of mass is g and the unit of mole is mol then m/n is the equivalent of g/mol which coincidentally is the unit of Molar mass.
To find the mass of 9.15 × 10²⁴ molecules of methanol (CH₃OH), we first need to determine the molar mass of methanol, which is approximately 32.04 g/mol. Using Avogadro's number (6.022 × 10²³ molecules/mol), we can convert the number of molecules to moles: ( n = \frac{9.15 \times 10^{24}}{6.022 \times 10^{23}} \approx 15.19 ) moles. Finally, we calculate the mass: ( \text{mass} = n \times \text{molar mass} = 15.19 , \text{mol} \times 32.04 , \text{g/mol} \approx 486.4 , \text{g} ).
To determine how many grams of NH₃ can be produced from 3.13 mol of N₂, we start with the balanced chemical equation: N₂ + 3H₂ → 2NH₃. From the equation, 1 mole of N₂ produces 2 moles of NH₃. Therefore, 3.13 moles of N₂ will produce 3.13 × 2 = 6.26 moles of NH₃. To convert moles of NH₃ to grams, we use its molar mass (approximately 17.03 g/mol): 6.26 mol × 17.03 g/mol = 106.36 grams of NH₃.
1 mol Na X (22.99 Na / mol Na) = 22.99 g Na1 mol N X (14.01 g N / mol N) = 14.01 g N3 mol O X (16.00 g O / mol O) = 48.00 g OMolar mass of NaNO3 = 85.00 g/mol