number of moles = mass/molar mass
mass = number of moles x molar mass
21mol x 14gmol-1 = 294g
molar mass of Nitrogen is 14, which you can find on a periodic table
That depends. In a solution used for silver staining in biochemical research, for example, silver nitrate is at 0.8%, sodium hydroxide at 1.9% and ammonium hydroxide at 1.4%, with the rest made up of sterile deionized water.
[ 217(g) / 44.013(g/mol) ] * 2(molN/molN2O) = 9.86 mol NDivide mass (g) by molar mass (g/mol) to get moles of N2O, this should be multiplied by 2 for the stoechiometric factor of atoms N per molecule N2O.
Approximally 0.275 moles. The molar mass of Ca C O3 is ~ 40+12+3*16 = 100g/mol 27.50g = x mol *100g/mol 27.50g/(100g/mol) = x mol 0.275 g/(g/mol) = x mol 0.275 mol = x mol
88.11 grams/mole
Since we need the mass percent, we need to know the molar mass of the entire compound: H - 1g/mol N- 14 g/mol O -32 g/mol (16 g/mol x 2) which equals 47 g/mol. now, put the weight of the unknown, N, over the entire weight. 14/47 = 29.8 g/mol
1 mol Na X (22.99 Na / mol Na) = 22.99 g Na1 mol N X (14.01 g N / mol N) = 14.01 g N3 mol O X (16.00 g O / mol O) = 48.00 g OMolar mass of NaNO3 = 85.00 g/mol
That depends. In a solution used for silver staining in biochemical research, for example, silver nitrate is at 0.8%, sodium hydroxide at 1.9% and ammonium hydroxide at 1.4%, with the rest made up of sterile deionized water.
Molecular mass = sum of all atoms masses = 1(molN/mol NH3)*14.01(g/mol N) + 3(molH/mol NH3)*1.008(g/mol H) = 17.03 g/mol NH3
1 mol Na X (22.99 Na / mol Na) = 22.99 g Na1 mol N X (14.01 g N / mol N) = 14.01 g N3 mol O X (16.00 g O / mol O) = 48.00 g OMolar mass of NaNO3 = 85.00 g/mol
To find the mole of a chemical from the given mass, use the formula mass = moles x molar mass or m = nM so to find the n... isolate the n first in the formula. n = m/M. The M signfies the Molar Mass of Hydrogen which is 1.008 g/mol and the m signifies the given mass of hydrogen which is 2.002 g. Divide 2.002 g by 1.008 g/mol which is 1.986 mol of H. Remember ... look at the units. In the formula, if you isolate M... M = m/n Since the unit of mass is g and the unit of mole is mol then m/n is the equivalent of g/mol which coincidentally is the unit of Molar mass.
I'm assuming that your instructor is using the terms mass and weight interchangeably. First determine the molar mass of each compound by multiplying the molar mass of each element by its subscript and add them together. The molar mass of an element is its atomic weight on the periodic table in grams. Molar mass of sodium nitrate (NaNO3) (1 atom Na x 22.98970g/mol Na) + (1 atom N x 14.0067g/mol N) + (3 atoms O x 15.9994g/mol O) = 84.9946g/mol NaNO3 Molar mass of carbon dioxide (CO2) (1 atom C x 12.0107g/mol C) + (2 atoms O x 15.9994g/mol O) = 44.0095g/mol CO2 Now multiply the molar mass for each compound by the number given and compare the results to determine which has the greater mass. 5mol NaNO3 x 84.9946g/mol NaNO3 = 424.973g NaNO3 4 mol CO2 x 44.0095g/mol CO2 = 176.038 So 5 moles of sodium nitrate has a mass greater than 4 moles of carbon dioxide.
[ 217(g) / 44.013(g/mol) ] * 2(molN/molN2O) = 9.86 mol NDivide mass (g) by molar mass (g/mol) to get moles of N2O, this should be multiplied by 2 for the stoechiometric factor of atoms N per molecule N2O.
Approximally 0.275 moles. The molar mass of Ca C O3 is ~ 40+12+3*16 = 100g/mol 27.50g = x mol *100g/mol 27.50g/(100g/mol) = x mol 0.275 g/(g/mol) = x mol 0.275 mol = x mol
88.11 grams/mole
Since we need the mass percent, we need to know the molar mass of the entire compound: H - 1g/mol N- 14 g/mol O -32 g/mol (16 g/mol x 2) which equals 47 g/mol. now, put the weight of the unknown, N, over the entire weight. 14/47 = 29.8 g/mol
1 mol K X (39.10 g K / mol K) = 39.10 g K1 mol N X (14.01 g N / mol N) = 14.01 g N3 mol O X (16.00 g O / mol O) = 48.00 g OMolar mass of KNO3 = 101.11 g/mol
1 mol Pb = 207.2 grams 12.4 mol Pb = ? grams (cross multiplication) mass of (12.4 mol Pb) = (207.2 gr *12.4 mol) / (1mol) = 2569.28 g