answersLogoWhite

0

Determine the mass of 21 mol N?

Updated: 4/28/2022
User Avatar

Wiki User

12y ago

Best Answer

number of moles = mass/molar mass

mass = number of moles x molar mass

21mol x 14gmol-1 = 294g

molar mass of Nitrogen is 14, which you can find on a periodic table

User Avatar

Wiki User

12y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Determine the mass of 21 mol N?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the mass of NaNO3?

1 mol Na X (22.99 Na / mol Na) = 22.99 g Na1 mol N X (14.01 g N / mol N) = 14.01 g N3 mol O X (16.00 g O / mol O) = 48.00 g OMolar mass of NaNO3 = 85.00 g/mol


What is percent composition of AgNO2?

That depends. In a solution used for silver staining in biochemical research, for example, silver nitrate is at 0.8%, sodium hydroxide at 1.9% and ammonium hydroxide at 1.4%, with the rest made up of sterile deionized water.


What is the molecular mass of NH3 when The atomic mass of N is 1401 gmole and the atomic mass of H is 1008 gmole?

Molecular mass = sum of all atoms masses = 1(molN/mol NH3)*14.01(g/mol N) + 3(molH/mol NH3)*1.008(g/mol H) = 17.03 g/mol NH3


What is the molar mass of nitrogen dioxide?

1 mol Na X (22.99 Na / mol Na) = 22.99 g Na1 mol N X (14.01 g N / mol N) = 14.01 g N3 mol O X (16.00 g O / mol O) = 48.00 g OMolar mass of NaNO3 = 85.00 g/mol


How many moles are in 2.002g of hydrogen?

To find the mole of a chemical from the given mass, use the formula mass = moles x molar mass or m = nM so to find the n... isolate the n first in the formula. n = m/M. The M signfies the Molar Mass of Hydrogen which is 1.008 g/mol and the m signifies the given mass of hydrogen which is 2.002 g. Divide 2.002 g by 1.008 g/mol which is 1.986 mol of H. Remember ... look at the units. In the formula, if you isolate M... M = m/n Since the unit of mass is g and the unit of mole is mol then m/n is the equivalent of g/mol which coincidentally is the unit of Molar mass.


Which weighs more 5moles of sodium nitrate or 4 moles of carbon dioxide?

I'm assuming that your instructor is using the terms mass and weight interchangeably. First determine the molar mass of each compound by multiplying the molar mass of each element by its subscript and add them together. The molar mass of an element is its atomic weight on the periodic table in grams. Molar mass of sodium nitrate (NaNO3) (1 atom Na x 22.98970g/mol Na) + (1 atom N x 14.0067g/mol N) + (3 atoms O x 15.9994g/mol O) = 84.9946g/mol NaNO3 Molar mass of carbon dioxide (CO2) (1 atom C x 12.0107g/mol C) + (2 atoms O x 15.9994g/mol O) = 44.0095g/mol CO2 Now multiply the molar mass for each compound by the number given and compare the results to determine which has the greater mass. 5mol NaNO3 x 84.9946g/mol NaNO3 = 424.973g NaNO3 4 mol CO2 x 44.0095g/mol CO2 = 176.038 So 5 moles of sodium nitrate has a mass greater than 4 moles of carbon dioxide.


How many moles of N are in 0.245g N2O?

[ 217(g) / 44.013(g/mol) ] * 2(molN/molN2O) = 9.86 mol NDivide mass (g) by molar mass (g/mol) to get moles of N2O, this should be multiplied by 2 for the stoechiometric factor of atoms N per molecule N2O.


Calculate the number of moles in 27.50 grams CaCO3?

Approximally 0.275 moles. The molar mass of Ca C O3 is ~ 40+12+3*16 = 100g/mol 27.50g = x mol *100g/mol 27.50g/(100g/mol) = x mol 0.275 g/(g/mol) = x mol 0.275 mol = x mol


Molar mass of N2O?

88.11 grams/mole


The mass percent nitrogen in nitrous acid HNO2 is?

Since we need the mass percent, we need to know the molar mass of the entire compound: H - 1g/mol N- 14 g/mol O -32 g/mol (16 g/mol x 2) which equals 47 g/mol. now, put the weight of the unknown, N, over the entire weight. 14/47 = 29.8 g/mol


What is the molar mass of KNO3?

1 mol K X (39.10 g K / mol K) = 39.10 g K1 mol N X (14.01 g N / mol N) = 14.01 g N3 mol O X (16.00 g O / mol O) = 48.00 g OMolar mass of KNO3 = 101.11 g/mol


Calculate the number of grams of lead Pb in 12.4 moles of lead?

1 mol Pb = 207.2 grams 12.4 mol Pb = ? grams (cross multiplication) mass of (12.4 mol Pb) = (207.2 gr *12.4 mol) / (1mol) = 2569.28 g