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What is the mass of NaNO3?

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Anonymous

9y ago
Updated: 3/21/2022

1 mol Na X (22.99 Na / mol Na) = 22.99 g Na

1 mol N X (14.01 g N / mol N) = 14.01 g N

3 mol O X (16.00 g O / mol O) = 48.00 g O

Molar mass of NaNO3 = 85.00 g/mol

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Related Questions

What is the percent concentration by mass of a solution 4.2g of NaNO3 in 60 g water?

4.2 grams NaNO3/60 grams water * 100 = 7% by mass -------------------


The solubility of NaNO3 at 20 C is 82 g per 100 grams of water What is the mass percent of a saturated solution of NaNO3?

The mass percent of a saturated solution of NaNO3 at 20°C can be calculated by dividing the mass of NaNO3 in the saturated solution (82 g) by the total mass of the solution (82 g NaNO3 + 100 g water) and then multiplying by 100%. This results in a mass percent of 82/182 * 100% ≈ 45.1%.


How many grams are in 1 mole of NaNO3?

The molar mass of NaNO3 is 85.0 g/mol. Therefore, 1 mole of NaNO3 is equal to 85.0 grams.


Could you convert .10 mol of NaNO3 to grams?

To convert 0.10 mol of NaNO3 to grams, you need to use the molar mass of NaNO3, which is 85 g/mol. Multiplying 0.10 mol by the molar mass will give you the answer: 0.10 mol x 85 g/mol = 8.5 grams of NaNO3.


What is the mass in grams of 0.254 mol sodium nitrate?

To find the mass in grams of 0.254 mol of sodium nitrate (NaNO3), you would multiply the number of moles by the molar mass of NaNO3. The molar mass of NaNO3 is 85 grams/mol. So, 0.254 mol x 85 g/mol = 21.59 grams of sodium nitrate.


How many moles of nitrogen N are in 60.0 g of nitrous oxide N2O?

For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3


What is the mass of 1 mol of NaNO3?

Using atomic weights for Na = 23 and N=14 and O = 16, one arrives at a mass for 1 mole of NaNO3 of23 + 14 + (3x16) = 85 grams/mole


What is the percentage of oxygen in sodium nitrate(NaNO3)?

The percentage of oxygen in sodium nitrate (NaNO3) is 53.9%. This is calculated by dividing the molar mass of oxygen in the compound by the molar mass of the entire compound and then multiplying by 100.


A solution contains 85.0 g of NaNO3 and has a volume os 750 mL find the molarity of the solution?

First, convert the mass of NaNO3 to moles using the molar mass of NaNO3. Then, calculate the molarity by dividing the moles of NaNO3 by the volume of the solution in liters. Molarity (M) = moles of solute / volume of solution in liters.


What is the mass of 6.0 moles of sodium nitrate (NaNO3)?

To find the mass of 6.0 moles of sodium nitrate (NaNO3), you first need to calculate the molar mass of NaNO3, which is 85.00 g/mol. Then, you multiply the molar mass by the number of moles: 85.00 g/mol x 6.0 mol = 510.0 g. Therefore, the mass of 6.0 moles of sodium nitrate is 510.0 grams.


What is the molecular mass of sodium nitrate?

The molecular mass of sodium nitrate is 84,9947.


What i the percentage by mass concentratioof a solution made by combining 12.0gof NaNO3 with 100.0g of water?

This percentage is 12 %.