1 mol Na X (22.99 Na / mol Na) = 22.99 g Na
1 mol N X (14.01 g N / mol N) = 14.01 g N
3 mol O X (16.00 g O / mol O) = 48.00 g O
Molar mass of NaNO3 = 85.00 g/mol
4.2 grams NaNO3/60 grams water * 100 = 7% by mass -------------------
The mass percent of a saturated solution of NaNO3 at 20°C can be calculated by dividing the mass of NaNO3 in the saturated solution (82 g) by the total mass of the solution (82 g NaNO3 + 100 g water) and then multiplying by 100%. This results in a mass percent of 82/182 * 100% ≈ 45.1%.
The molar mass of NaNO3 is 85.0 g/mol. Therefore, 1 mole of NaNO3 is equal to 85.0 grams.
To convert 0.10 mol of NaNO3 to grams, you need to use the molar mass of NaNO3, which is 85 g/mol. Multiplying 0.10 mol by the molar mass will give you the answer: 0.10 mol x 85 g/mol = 8.5 grams of NaNO3.
To find the mass in grams of 0.254 mol of sodium nitrate (NaNO3), you would multiply the number of moles by the molar mass of NaNO3. The molar mass of NaNO3 is 85 grams/mol. So, 0.254 mol x 85 g/mol = 21.59 grams of sodium nitrate.
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3
Using atomic weights for Na = 23 and N=14 and O = 16, one arrives at a mass for 1 mole of NaNO3 of23 + 14 + (3x16) = 85 grams/mole
The percentage of oxygen in sodium nitrate (NaNO3) is 53.9%. This is calculated by dividing the molar mass of oxygen in the compound by the molar mass of the entire compound and then multiplying by 100.
First, convert the mass of NaNO3 to moles using the molar mass of NaNO3. Then, calculate the molarity by dividing the moles of NaNO3 by the volume of the solution in liters. Molarity (M) = moles of solute / volume of solution in liters.
To find the mass of 6.0 moles of sodium nitrate (NaNO3), you first need to calculate the molar mass of NaNO3, which is 85.00 g/mol. Then, you multiply the molar mass by the number of moles: 85.00 g/mol x 6.0 mol = 510.0 g. Therefore, the mass of 6.0 moles of sodium nitrate is 510.0 grams.
The molecular mass of sodium nitrate is 84,9947.
This percentage is 12 %.