i have know idea
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∙ 12y ago1/103.4= 4.0 x 10 -4 M HNO3==============
pH = - log10 [H+], where [H+] is the molar concentration of hydrogen ions. HNO3 is a strong acid and dissociates completely in water so a 5 M solution of HNO3 would have a concentration of hydrogen ions of 5M also. So, pH = -log10[5] = -0.699 which indicates an extremely strong acid.
Use the equation; MaVa= MbVbWhere M is Molarity and V is volume.For this question, the left side of the equation is the information for 0.12M HNO3The unknown will be x on the right of the equation (replace Vb with x and solve for x).After the answer is found, it will need to be converted to mL, 1 L=1000mL
500 x .50/1000 x 1/1 x 1000/6.0 = 41.7 = 42 mL HNO3
1.0 Moles
10
1/103.4= 4.0 x 10 -4 M HNO3==============
pH = - log10 [H+], where [H+] is the molar concentration of hydrogen ions. HNO3 is a strong acid and dissociates completely in water so a 5 M solution of HNO3 would have a concentration of hydrogen ions of 5M also. So, pH = -log10[5] = -0.699 which indicates an extremely strong acid.
Use the equation; MaVa= MbVbWhere M is Molarity and V is volume.For this question, the left side of the equation is the information for 0.12M HNO3The unknown will be x on the right of the equation (replace Vb with x and solve for x).After the answer is found, it will need to be converted to mL, 1 L=1000mL
The average of 6, 15 and m is (6 + 15 + m) / 3 = (21 + m)/3 = 7 + m/3
500 x .50/1000 x 1/1 x 1000/6.0 = 41.7 = 42 mL HNO3
Molarity = moles of solute/Liters of solution ( get moles of HNO3 and 300 ml = 0.300 Liters ) 0.31 grams Nitric acid (1 mole HNO3/63.018 grams) = 0.004919 moles HNO3 Molarity = 0.004919 moles HNO3/0.300 Liters = 0.0164 M HNO3
1.0 Moles
0.289 Moles is the molarity of an NaOH solution if 4.37 ml is titrated by 11.1 ml of 0.0904m hno3.
if the question were 15 M of F then answer is 15 Minutes of Fame which was a quote from Andy Warhol
If you mean m^2 -8m +15 then it equals (m -3)(m -5) when factored
1.00 * 10^-14/ 0.34 = 2.9^-14 M or (3.2e-14 M)