Bolt Circle
THREE CLASSES OF LEVER There are three classes of lever and each class has fulcrum, load and effort which together can move a heavy weight. CLASS 1 The workman uses a trolley to move the large packing case. The fulcrum is the wheel. CLASS 2The gardener uses a wheel barrow to lift tools and garden waste. The load is in the centre of the barrow CLASS 3 The fisherman catches the fish which becomes the load at the end of the lever.
I'm not sure if you're asking for just the equation for the reactions, or how to calculate the FEM of a cantilever via the Moment Distribution method (aka Hardy Cross method), so I'll anser both.If you assume clockwise moments are negative...If your cantilevered span has a length "L", and a uniform load "W" acting downward along the entirelength of the span, then the fixed end moment is (W*L2)/8If the fixed end is to the left, the equation is positive (the load is acting clockwise, so the reacting FEM is counter-clockwise, therefore positive.) If the fixed end is on the right, the equation becomes -(W*L2)/8If your uniform load W is acting downward, and is acting along length "d" (which is NOT the entire span), its easiest to convert the uniform load W to a point load "P", where P = W*dThen your FEM = [P*a*b*(2*L-a)]/(2*L2)where:L = entire length of spana = distance P is acting from the fixed end,b = distance P is acting from the cantilevered end (also, b = L - a)OR, if W is centered along the span (therefore Pis also centered), then the equation becomes (3*P*L)/16When going through the distributive process, the cantilevered end will ALWAYS have a final moment of zero. At the fixed point, the cantilevered side has a distribution factor of zero, while the other side has a D.F. of one. So, if you have length ABCD, where A is a cantelever, and B, C and D are assumed fixed, FEMAB = 0, D.F.BA = 0, D.F.BC = 1, and D.F.CB = D.F.CD = D.F.DC = 0.5So what ends up happening is that the final FEM for the cantilever ("AB") is zero, and the opposite end of the span ("BA") remains as its initial value. The reason for this is when you sum up the reactions at the point (in this case B) supporting the cantilever and flip the sign, the distribution factors tell you to distribute everything to the side of the support opposite the cantilever ( -(FEMBA + FEMBC) is added to FEMBC). So you can go through the Cross Method as normal, but you don't touch AB or BA, and BC is adjusted only the once that I just mentioned (you don't carry over the 1/2 reactions from CB).
what does bc lamt stand for
bc probably stands for birth control
It can stand for anything really
bernando chavez , the founder of the company
Battery Commander's Telescope M1915A1
before christ
Broadcast
BC = Before Christ AD = Anno Domini
BC is "before Christ" and AD "anno domini"
Before Christ
Before Christ
before christ