It reacts with it. The reaction is a redx reaction. Nitrogen is reduced (its oxidation number goes from 0 to -3) and hydrogen is oxidised (its oxidation number goes from 0 to +1)
Put a 2 to NH3 first.Then a 3 to Hydrogen.
Three: The reaction equation is N2 + 3 H2 -> 2 NH3
16,45 g nitrogen are needed.
8 mol
The formula for the synthesis of ammonia from diatomic nitrogen and hydrogen is: N2+3H2-->2NH3
(N2) + 3(H2) = 2(NH3)
H2 n2
Ammonia
First you have to balance the equation N2 + H2 ---> NH3 N2 +3H2 ---> 2NH3 Then you have to use the Molecular Weight and number of mols required for complete reaction of each one to go from 14g N2 + xg of H2 to get the final result.
NH3 is made by N2 and H2. pure NH3 is clean ammonia.
Put a 2 to NH3 first.Then a 3 to Hydrogen.
Three: The reaction equation is N2 + 3 H2 -> 2 NH3
16,45 g nitrogen are needed.
You need the balanced chemical equation for N2 and H2 combining to form ammonia, NH3.N2 (g) + 3 H2 (g) -----> 2 NH3 (g)Moles NH3 = ( 55.5 g NH3 ) / ( 17.03 g/mol NH3 ) = 3.259 moles of NH3n N2 required = ( 3.259 mol NH3 ) ( 1 N2 mol / 2 NH3 mol ) = 1.629 moles N2m N2 required = ( 1.629 mol N2 ) ( 28.103 g N2 / mol N2 ) = 45.67 g N2 needed
1/2 n2 + 3/2 h2 = nh3 sorry about the lower case they wouldn't let me summit it with caps N2 + 3 H2 => 2 NH3
This is a synthesis reaction.
N2 + 3H2 -> 2NH3 If you have moles produced you can do it this way. 22.5 moles NH3 (3 moles H2/2 moles NH3) = 33.8 moles H2 needed -----------------------------------