you start with the 5.00g PbCl2 then use a conversion factor for the molar mass of pbcl2 (1mol pbcl2/278.1gpbcl2) now from mol pbcl2 use another conversion factor to get g cl2 (70.90gCl2/1 mol PbCl2) do the math and you wind up with 1.27 g Cl2
Zn + PbCl2 --> Pb + ZnCl2
Pb(OH)2 + 2HCl --> PbCl2 + 2H2O
yes
No
you start with the 5.00g PbCl2 then use a conversion factor for the molar mass of pbcl2 (1mol pbcl2/278.1gpbcl2) now from mol pbcl2 use another conversion factor to get g cl2 (70.90gCl2/1 mol PbCl2) do the math and you wind up with 1.27 g Cl2
Zn + PbCl2 --> Pb + ZnCl2
KCl is soluble. PbCl2 is insoluble. Test their solubilities in water.
Pb(OH)2 + 2HCl --> PbCl2 + 2H2O
yes
No
To determine the number of atoms of chlorine in 445g of lead chloride (PbCl2), you need to calculate the number of moles of PbCl2 in 445g and then multiply it by the number of chlorine atoms in one PbCl2 molecule. First, calculate the number of moles of PbCl2 using the formula: moles = mass / molar mass. The molar mass of PbCl2 is 278.1 g/mol, so moles = 445g / 278.1 g/mol = 1.6 moles. Since there are two chlorine atoms in one molecule of PbCl2, the total number of chlorine atoms is 2 * 1.6 moles = 3.2 moles of chlorine atoms. To convert moles to atoms, multiply by Avogadro's number. Therefore, there are 3.2 moles * 6.022 x 10^23 atoms/mole = 1.9264 x 10^24 atoms of chlorine in 445g of PbCl2.
The chlorine in PbCl2 exists as chloride ions, and the oxidation number of chloride ions is always -1.
Pbcl2
Formula: PbCl2
Lead Chloride.
PbCl4 is it's formula. The name of the chemical is Lead tetrachloride.