PbBr2 is only slightly soluble in water, but more so than PbCl2, so if you had to write the equation it would be2LiCl(aq) + PbBr2(aq) ==> 2LiBr(aq) + PbCl2(s)
no,because it has a cloride ion and all clorides are soluble
Yes, because the equation is balanced
Sulfur hexafluoride
Pb(IV)-compositions are good oxidants. Pb(II) is more stable. Inert-Pair-Effect.
PbCl4 is it's formula. The name of the chemical is Lead tetrachloride.
you start with the 5.00g PbCl2 then use a conversion factor for the molar mass of pbcl2 (1mol pbcl2/278.1gpbcl2) now from mol pbcl2 use another conversion factor to get g cl2 (70.90gCl2/1 mol PbCl2) do the math and you wind up with 1.27 g Cl2
Zn + PbCl2 --> Pb + ZnCl2
Lead and Chlorine
the first one is Lead (II) Chloride.. :)
KCl is soluble. PbCl2 is insoluble. Test their solubilities in water.
Pb(OH)2 + 2HCl --> PbCl2 + 2H2O
PbCl2 is lead(II) chloride, PbCl4 is lead(IV) chloride
yes
No
To determine the number of atoms of chlorine in 445g of lead chloride (PbCl2), you need to calculate the number of moles of PbCl2 in 445g and then multiply it by the number of chlorine atoms in one PbCl2 molecule. First, calculate the number of moles of PbCl2 using the formula: moles = mass / molar mass. The molar mass of PbCl2 is 278.1 g/mol, so moles = 445g / 278.1 g/mol = 1.6 moles. Since there are two chlorine atoms in one molecule of PbCl2, the total number of chlorine atoms is 2 * 1.6 moles = 3.2 moles of chlorine atoms. To convert moles to atoms, multiply by Avogadro's number. Therefore, there are 3.2 moles * 6.022 x 10^23 atoms/mole = 1.9264 x 10^24 atoms of chlorine in 445g of PbCl2.
The chlorine in PbCl2 exists as chloride ions, and the oxidation number of chloride ions is always -1.