I'm assuming that 2 is supposed to be a subscript, which would make that a negatively-charged ion consisting of two sulfur atoms. The aq means "aqueous" which means the ion is dissolved in water.
2K+(aq) + S2–(aq)
Na+(aq), I-(aq)
Ionisation in solution is not a chemical reaction. It can be written as one but still it's NOT: only physical change of state ( subscripted between brackets (s) or (aq) ) Na2S(s) --> 2Na+(aq) + S2-(aq)
Net Ionic: Cd^+2+(aq) + S^2-(aq) ==> CdS(s)The Na^+ and Cl^- are spectator ions.
Cd^2+(aq) + 2Cl^-(aq) +2Na^+(aq) + S^2-(sq) ==> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)The 2Na^+(aq) and the 2 Cl^-(aq) are spectator ions as they appear on both sides of the equation. Thus, the NET reaction is ...Cd^2+(aq) + S^2-(aq) ==> CdS(s)What else was your question. This is classed as a double replacement reaction.
2K+(aq) + S2–(aq)
Na+(aq), I-(aq)
Complete ionic equation: Pb2+(aq) + NO3-(aq) + 2Na+(aq) + S2-(aq) --> PbS(s) + 2Na+(aq) + NO3-(aq) Net ionic equation: Pb2+(aq) + S2-(aq) --> PbS(s)
Add a solution of magnesium chloride; magnesium hydroxide is not soluble in water.
In chemistry, "aq" stands for "aqueous," indicating that a substance is dissolved in water. It is commonly used in chemical equations to represent a solution where the solute is dissolved in water.
Ionisation in solution is not a chemical reaction. It can be written as one but still it's NOT: only physical change of state ( subscripted between brackets (s) or (aq) ) Na2S(s) --> 2Na+(aq) + S2-(aq)
For the molecular balance of the equation it would be: CuSO4 (aq) + Na2S (aq) = CuS (s) + Na2SO4 (aq). For the net ionic balance of the equation it would be: Cu2+ (aq) + S2(aq) = CuS (s).
Net Ionic: Cd^+2+(aq) + S^2-(aq) ==> CdS(s)The Na^+ and Cl^- are spectator ions.
Ag+(aq)+S2- ------> AgS+(s)
There's nothing to drive the reaction, since all the possible combinations are soluble. Before, you would have copper, sodium, chloride and sulfate ions in solution; after, you would have the same thing. It's not really a reaction if nothing happens.
Cd^2+(aq) + 2Cl^-(aq) +2Na^+(aq) + S^2-(sq) ==> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)The 2Na^+(aq) and the 2 Cl^-(aq) are spectator ions as they appear on both sides of the equation. Thus, the NET reaction is ...Cd^2+(aq) + S^2-(aq) ==> CdS(s)What else was your question. This is classed as a double replacement reaction.
Step 1: Write the balanced "molecular" equation:H2S + 2 NaOH Na2S + 2 H2OStep 2: Consult the solubility and strong electrolyte rules linked above to determine whether each substance will dissociate:H2S+2 NaOHNa2S+2 H2OnoyesyesStep 3: Dissociate all soluble salts, strong acids, and strong bases (except calcium hydroxide). Leave together all "not soluble" salts and weak acids or bases:H2S (aq) + 2Na+ (aq) + 2OH- (aq) 2Na+ (aq) + S2- (aq) + 2 H2O (l)Step 4: Cross out "spectator ions" that appear on both sides of the reaction (these ions do not participate in the chemistry) and rewrite the "net" reaction using the smallest possible coefficients.H2S (aq) + 2OH- (aq) S2- (aq) + 2H2O (l)