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I'm assuming that 2 is supposed to be a subscript, which would make that a negatively-charged ion consisting of two sulfur atoms. The aq means "aqueous" which means the ion is dissolved in water.
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When potassium sulfide dissociates how many particles are left?
2K+(aq) + S2–(aq)
Write the ions present in solution of Cu C2H3O2 2 and identify all of the phases in your answers?
Na+(aq), I-(aq)
What type of reaction is CuCl2 Na2S?
Ionisation in solution is not a chemical reaction. It can be written as one but still it's NOT: only physical change of state ( subscripted between brackets (s) or (aq) ) Na2S(s) --> 2Na+(aq) + S2-(aq)
Given the complete ionic equation Cd2 plus (aq) plus 2Cl-(aq) plus 2Na plus (aq) plus S2-(aq) CdS(s) plus 2Na plus (aq) plus 2Cl-(aq)?
Net Ionic: Cd^+2+(aq) + S^2-(aq) ==> CdS(s)The Na^+ and Cl^- are spectator ions.
Cd2 plus (aq) plus 2Cl-(aq) plus 2Na plus (aq) plus S2-(aq) CdS(s) plus 2Na plus (aq) plus 2Cl-(aq)?
Cd^2+(aq) + 2Cl^-(aq) +2Na^+(aq) + S^2-(sq) ==> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)The 2Na^+(aq) and the 2 Cl^-(aq) are spectator ions as they appear on both sides of the equation. Thus, the NET reaction is ...Cd^2+(aq) + S^2-(aq) ==> CdS(s)What else was your question. This is classed as a double replacement reaction.
When potassium sulfide dissociates how many particles are left?
2K+(aq) + S2–(aq)
Write the ions present in solution of Cu C2H3O2 2 and identify all of the phases in your answers?
Na+(aq), I-(aq)
What is the complete ionic equation for lead II nitrate and sodium sulfate?
Complete ionic equation: Pb2+(aq) + NO3-(aq) + 2Na+(aq) + S2-(aq) --> PbS(s) + 2Na+(aq) + NO3-(aq) Net ionic equation: Pb2+(aq) + S2-(aq) --> PbS(s)
What can be added to a solution of OH- (aq) S2- (aq) and SO42- (aq) ions to precipitate the OH- (aq) ions but not the others?
Add a solution of magnesium chloride; magnesium hydroxide is not soluble in water.
What do the letters aq mean?
In chemistry, "aq" stands for "aqueous," indicating that a substance is dissolved in water. It is commonly used in chemical equations to represent a solution where the solute is dissolved in water.
What type of reaction is CuCl2 Na2S?
Ionisation in solution is not a chemical reaction. It can be written as one but still it's NOT: only physical change of state ( subscripted between brackets (s) or (aq) ) Na2S(s) --> 2Na+(aq) + S2-(aq)
What is the molecular equation of CuNO32and NaS2?
For the molecular balance of the equation it would be: CuSO4 (aq) + Na2S (aq) = CuS (s) + Na2SO4 (aq). For the net ionic balance of the equation it would be: Cu2+ (aq) + S2(aq) = CuS (s).
Given the complete ionic equation Cd2 plus (aq) plus 2Cl-(aq) plus 2Na plus (aq) plus S2-(aq) CdS(s) plus 2Na plus (aq) plus 2Cl-(aq)?
Net Ionic: Cd^+2+(aq) + S^2-(aq) ==> CdS(s)The Na^+ and Cl^- are spectator ions.
What is the net ionic equation for the reaction of silver nitrate and ammonium sulphide?
Ag+(aq)+S2- ------> AgS+(s)
What happens when copper sulphate react with potassium cyanide?
There's nothing to drive the reaction, since all the possible combinations are soluble. Before, you would have copper, sodium, chloride and sulfate ions in solution; after, you would have the same thing. It's not really a reaction if nothing happens.
Cd2 plus (aq) plus 2Cl-(aq) plus 2Na plus (aq) plus S2-(aq) CdS(s) plus 2Na plus (aq) plus 2Cl-(aq)?
Cd^2+(aq) + 2Cl^-(aq) +2Na^+(aq) + S^2-(sq) ==> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)The 2Na^+(aq) and the 2 Cl^-(aq) are spectator ions as they appear on both sides of the equation. Thus, the NET reaction is ...Cd^2+(aq) + S^2-(aq) ==> CdS(s)What else was your question. This is classed as a double replacement reaction.
What is the equation for the reaction of sulfurous acid and sodium hydroxide?
Step 1: Write the balanced "molecular" equation:H2S + 2 NaOH Na2S + 2 H2OStep 2: Consult the solubility and strong electrolyte rules linked above to determine whether each substance will dissociate:H2S+2 NaOHNa2S+2 H2OnoyesyesStep 3: Dissociate all soluble salts, strong acids, and strong bases (except calcium hydroxide). Leave together all "not soluble" salts and weak acids or bases:H2S (aq) + 2Na+ (aq) + 2OH- (aq) 2Na+ (aq) + S2- (aq) + 2 H2O (l)Step 4: Cross out "spectator ions" that appear on both sides of the reaction (these ions do not participate in the chemistry) and rewrite the "net" reaction using the smallest possible coefficients.H2S (aq) + 2OH- (aq) S2- (aq) + 2H2O (l)
