I'm assuming that 2 is supposed to be a subscript, which would make that a negatively-charged ion consisting of two sulfur atoms. The aq means "aqueous" which means the ion is dissolved in water.
Cd^2+(aq) + 2Cl^-(aq) +2Na^+(aq) + S^2-(sq) ==> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)The 2Na^+(aq) and the 2 Cl^-(aq) are spectator ions as they appear on both sides of the equation. Thus, the NET reaction is ...Cd^2+(aq) + S^2-(aq) ==> CdS(s)What else was your question. This is classed as a double replacement reaction.
2K+(aq) + S2–(aq)
The net ionic equation is Cd2+(aq) + S2-(aq) -> CdS(s). This equation represents the actual chemical change happening in the reaction where cadmium ions and sulfide ions combine to form solid cadmium sulfide. The spectator ions, Na+ and Cl-, are present on both sides of the equation but do not participate in the reaction.
In solution, CuC2H3O2 would dissociate into Cu2+ and C2H3O2- ions. The phases involved would be solid CuC2H3O2 dissociating into aqueous Cu2+ and C2H3O2- ions.
The ionization equation for H2S is: H2S (aq) --> H+ (aq) + HS- (aq)
Cd^2+(aq) + 2Cl^-(aq) +2Na^+(aq) + S^2-(sq) ==> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)The 2Na^+(aq) and the 2 Cl^-(aq) are spectator ions as they appear on both sides of the equation. Thus, the NET reaction is ...Cd^2+(aq) + S^2-(aq) ==> CdS(s)What else was your question. This is classed as a double replacement reaction.
Add a solution of magnesium chloride; magnesium hydroxide is not soluble in water.
In chemistry, "aq" stands for "aqueous," indicating that a substance is dissolved in water. It is commonly used in chemical equations to represent a solution where the solute is dissolved in water.
2K+(aq) + S2–(aq)
The net ionic equation is Cd2+(aq) + S2-(aq) -> CdS(s). This equation represents the actual chemical change happening in the reaction where cadmium ions and sulfide ions combine to form solid cadmium sulfide. The spectator ions, Na+ and Cl-, are present on both sides of the equation but do not participate in the reaction.
The complete ionic equation for lead(II) nitrate (Pb(NO3)2) and sodium sulfate (Na2SO4) would be: Pb2+(aq) + 2NO3-(aq) + 2Na+(aq) + SO4^2-(aq) -> PbSO4(s) + 2Na+(aq) + 2NO3-(aq) In the equation, PbSO4 is the insoluble product formed when lead(II) ions from lead(II) nitrate react with sulfate ions from sodium sulfate.
In solution, CuC2H3O2 would dissociate into Cu2+ and C2H3O2- ions. The phases involved would be solid CuC2H3O2 dissociating into aqueous Cu2+ and C2H3O2- ions.
CuCl2(aq) + K2S(aq) --> CuS(s) + 2KCl(aq) K and Cl are spectators so the net ionic would be: Cu2+(aq) + S2-(aq) --> CuS(s)
The ionization equation for H2S is: H2S (aq) --> H+ (aq) + HS- (aq)
They are the state symbols in a chemical reaction. s = solid l = (pure) liquid g = gas aq = aqueous ( water) solution.
Ionisation in solution is not a chemical reaction. It can be written as one but still it's NOT: only physical change of state ( subscripted between brackets (s) or (aq) ) Na2S(s) --> 2Na+(aq) + S2-(aq)
Aqueous. (Dissolved in water) Example: CaCl2(aq)= Aqueous Calcium Chloride.