R- Reason E- Experimental Design (Procedure shortened) C- Call Back Data C- Compare to Hypothesis A- Analyze your data L- Lapses (possible errors) L -Light Bulb (something you learned) Hope this helps.
It stands for Reflector - specifically referring to Standard Reflector (which is round) as opposed to other varieties such as ER - Elliptical Reflector. There are many designations when it comes to light bulbs. This question refers to the bulbs shape designated by one or more letters, followed by a series of numbers. The letters represent the type and the numbers represent the diameter. The location or region typically designates the units of the diameter (mm vs. inches).
It is the type of refigerant gas
ns ney
I was also searching for the same but according to me the lamps with higher wattage should glow brighter. We know that, P=VI In series connection current is same through all the lamps but voltage across each lamp depends on the wattage of the bulb. So the bulb with higher wattage will draw more voltage and glow brighter.AnswerUnfortunately, the previous answer is incorrect, although it seems* to be the logical answer! The higher-wattage lamp has a lower resistance than the lower-wattage lamp. So, when they are connected in series, the larger voltage drop (IR)will appear across the lower-wattage lamp. As power is proportional to the square of the voltage, it is the lower-wattage lamp that will be the brighter.[*Many people have the mistaken belief that a higher-wattage lamp has a higher resistance than a lower-wattage lamp. That's the wrong way around!]
light r bulb same power taken
The current if the light bulbs are parallel is I= V/R where V is the voltage and R is the resistance of the bulb.
yeah a h1 bulb
open trunk, remove replastic trim/bulb holder, r/r (remove/replace) blown bulb See sources and related links below for bulb information.
home depot
You have a bad ground on that brake light bulb.
Volt (V) = Resistance (R) times Current (I) therefor R = V / I 30 Ω = 3V / 0.1A
r/h side fog bracket
I=v/r =110/121 =0.909A
The formula you are looking for is R = W/I x I.
Lumens is the total amount of light a light source (a light bulb, for instance) throws in all directions. Lux (lumens per square meter) can measure how intense light from that light source is when looking toward it from a certain distance. Lux depends greatly on how far away you are from a light source. At any given instant, light is thrown from the source in a perfect sphere.If you are trying to calculate how many lumens your light bulb shines and you have a light meter that gives you lux, point your meter at the light, then take your lux multiply by 12.57 (pi times 4). Then, multiply this by the distance of your light meter from the light bulb (in meters) squared. That will give you the lumens of the light bulb. In equation form, where lm is lumens, r is your distance from the light source, and pi is (come on) about 3.14, lux=lm/(pi*4*(r^2)), or lm=lux*pi*4*(r^2). The (pi*4*(r^2)) part is used to calculate the surface area of a sphere around the light source.Note: this calculation does not account for reflected light, and will only work on an exposed light bulb. Lights housed in a reflective cone (like in a flashlight) are designed to project light in one direction and (within the spot where light is projected) will have a lux much higher at any given distance than if the light bulb wasn't housed in a cone.
I = E/R = 120/25 = 4.8 amperes