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What else can I help you with?
What does roman numeral w mean?
There is no Roman numeral W. There is I, V, X, L, C, D and M but no W.
How do you do you equals VW plus z in algebra?
I'm assuming you mean the symbol (u) and not 'you'So:u = vw + zWhere vw means v * w (v times w)
If you is orthogonal to v and w then is u orthogonal to v plus w?
yes. not sure of the proof though.
What is a Vectorial Angle?
"Vectorial angle" is not a standard term in mathematics. The angle between two vectors v and w is defined as the value theta such that w dot v = v times w times cosine theta. Definitions: w and v are vectors (ordered lists of numbers) of the same dimension n (i.e. both contain n terms). The jth term in w is denoted wj (similarly for v) w dot v = w1v1 + w2v2 +... + wnvn w = square root of w dot w (similarly for w) We always choose theta to be between 0 and pi (i.e. between 0 and 180 degrees), including 0 and pi as possible values of course. If w is a positive multiple of v, theta will be zero. If w is a negative multiple of v, theta will be pi.
What is L in the equation V equals one third of parentheses L plus WL parentheses?
V=1/3(l+wl) v=1/3l(1+w) 3v=l(1+w) 3v/(1+w)=l
In a 100 watt light bulb how many volts are in it?
If it's a 100 W bulb that does not say everything about it. It could be a 12 v, 24 v, 120 v or a 230 v bulb, or other voltage. Look on the case or the packet.
How much current does a 75-W bulb require in a 100-W circut?
To determine the current required by a 75-W bulb in a 100-W circuit, we first need to know the voltage of the circuit. Assuming a standard voltage of 120 volts, the current can be calculated using the formula ( I = P/V ), where ( P ) is power in watts and ( V ) is voltage in volts. For a 75-W bulb, the current would be ( I = 75 , \text{W} / 120 , \text{V} = 0.625 , \text{A} ). Thus, the 75-W bulb requires approximately 0.625 amperes of current.
The current in a 100-W bulb connected to a 120-V source is?
The apparent answer to the question would be (100 W)/(120 V) = 0.8333 A, assuming that, as a pure resistance load, the light bulb has a power factor close to 1.0.
What power does a light bulb with 120V and 5A have?
Power= V * A so 120 V * 5 A = 600 W (J/s)
How much amount of current does a 14 watt cfl bulb consumes?
A 240 v 14 w cfl bulb uses about 0.14 amps.
When compared in a given time interval with other light bulbs connected to a 120 V circuit a 60 W lightbulb?
A 60 W light bulb consumes more power (produces more light) than a 40 W light bulb in a given time interval when both are connected to a 120 V circuit. This is because power is directly proportional to the wattage rating of the light bulb.
Which equation should be used to calculate how much current in amps is required to achieve the full 100 W output from the 9 V bulb?
I = p/v = 100w/9v = 11.11ai = p*v = 100w*9v = 900ai = (p/2)*v = 50w*9v = 450ai = p*2*v = 100w*(9v + 9v) = 8100a
What voltage is required to pass 0.5 A of current through a 4.5-W BULB?
To determine the voltage required to pass 0.5 A of current through a 4.5-W bulb, you can use the formula P = V * I, where P is power, V is voltage, and I is current. Given that power is 4.5 W and current is 0.5 A, you can rearrange the formula to solve for voltage: V = P / I. Plugging in the values, V = 4.5 W / 0.5 A, which equals 9 volts. Therefore, 9 volts is required to pass 0.5 A of current through a 4.5-W bulb.
Can a 85 watt headlight bulb be used to replace a 45 watt fog light bulb?
To do any replacements of different bulbs you have to consider what the new current will be and if the wire size and fuse will be able to take the new current (amps). Use this formula, W = A x V or A = W/V.
How much current would flow through a 75 w bulb in a 220 v curcuit?
The formula you are looking for is I = W/E. Amps = Watts/Volts.
On a Volvo 850 Wagon what does the indicator light with the light bulb w an exclamation point mean?
it means that a bulb is burned out
A 100w electric light bulb is connected to 200v supply calculate the current following in the bulb?
40W Bulb will spiol due to over current passing through its coilAnswerSince the 40-W lamp has a higher resistance than the 100-W lamp, the greater voltage drop will appear the 40 W lamp. As a result the 40 W lamp will be subjected to a voltage beyond its 100-V rating, and the 100-W lamp will be subjected to a voltage below its 100-V rating. Therefore, the 40-W lamp will burn much more brightly than the 100-W lamp.Incidentally, the symbols for the 'watt' and 'volt' are upper, not lower, case: W and V.
