V on a light bulb means volts. W means watts.
V can mean Volts and W is Watts.
There is no Roman numeral W. There is I, V, X, L, C, D and M but no W.
I'm assuming you mean the symbol (u) and not 'you'So:u = vw + zWhere vw means v * w (v times w)
yes. not sure of the proof though.
"Vectorial angle" is not a standard term in mathematics. The angle between two vectors v and w is defined as the value theta such that w dot v = v times w times cosine theta. Definitions: w and v are vectors (ordered lists of numbers) of the same dimension n (i.e. both contain n terms). The jth term in w is denoted wj (similarly for v) w dot v = w1v1 + w2v2 +... + wnvn w = square root of w dot w (similarly for w) We always choose theta to be between 0 and pi (i.e. between 0 and 180 degrees), including 0 and pi as possible values of course. If w is a positive multiple of v, theta will be zero. If w is a negative multiple of v, theta will be pi.
V=1/3(l+wl) v=1/3l(1+w) 3v=l(1+w) 3v/(1+w)=l
If it's a 100 W bulb that does not say everything about it. It could be a 12 v, 24 v, 120 v or a 230 v bulb, or other voltage. Look on the case or the packet.
The apparent answer to the question would be (100 W)/(120 V) = 0.8333 A, assuming that, as a pure resistance load, the light bulb has a power factor close to 1.0.
Power= V * A so 120 V * 5 A = 600 W (J/s)
The resistance is equal to the voltage-squared divided by the power. So a 1kW heater is 52.9 ohms, a 100 watt bulb is 529 ohms. The basic formula is W = V^2 / R
A 240 v 14 w cfl bulb uses about 0.14 amps.
To do any replacements of different bulbs you have to consider what the new current will be and if the wire size and fuse will be able to take the new current (amps). Use this formula, W = A x V or A = W/V.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
40W Bulb will spiol due to over current passing through its coilAnswerSince the 40-W lamp has a higher resistance than the 100-W lamp, the greater voltage drop will appear the 40 W lamp. As a result the 40 W lamp will be subjected to a voltage beyond its 100-V rating, and the 100-W lamp will be subjected to a voltage below its 100-V rating. Therefore, the 40-W lamp will burn much more brightly than the 100-W lamp.Incidentally, the symbols for the 'watt' and 'volt' are upper, not lower, case: W and V.
it means that a bulb is burned out
A 60 watt incandescent bulb using 120 Volts draws about one-half amp. Watts = Volts x Amps (For a resistive load). By Ohm's Law Volts = Current x Resistance so R = 120 V / .5 A = 240 Ohms. Doing the same math for a 40 watt bulb you get 360 Ohms.
There is no Roman numeral W. There is I, V, X, L, C, D and M but no W.
A table lamp with a 60 w bulb uses ¼ amp on a European 240 v system, or ½ amp on an American 120 v system.