Study guides

☆☆

Q: What does it mean by writing V and W in a bulb?

Write your answer...

Submit

Still have questions?

Related questions

If it's a 100 W bulb that does not say everything about it. It could be a 12 v, 24 v, 120 v or a 230 v bulb, or other voltage. Look on the case or the packet.

The apparent answer to the question would be (100 W)/(120 V) = 0.8333 A, assuming that, as a pure resistance load, the light bulb has a power factor close to 1.0.

There are zero amps in a 300 watt bulb. Watts are the product of amps times volts. W = A x V. To find amperage use the equation A = W/V. If you find the voltage of the 300 watt bulb uses, divide the wattage by the voltage and it will give you the amps of a 300 watt bulb.

Power= V * A so 120 V * 5 A = 600 W (J/s)

Recall power P = V2/R For a constant V, P is inversely related to the resistance of the filament. Hence 40 W bulb would have more resistance than that of 200 W bulb.

It is expressing a change in the value of something as a percentage of its original value. So, if the original value (V) changes to the new value (W) then the change is W - V. Then, the relative change is (W - V)/V and the percentage change is 100*(W - V)/V = 100*(W/V - 1)

Power (w) = Volts (v) * Current (I) I = P/V 100w bulb = 100/230 = 434mA 40w bulb = 40/230 = 174mA

A 240 v 14 w cfl bulb uses about 0.14 amps.

The amps times the volts equals the watts. A 120 v 60 w lamp takes ½ amp, while a 240 v 60 w lamp takes ¼ amp

0.909 Amps

it means that a bulb is burned out

The formula you are looking for is I = W/E. Amps = Watts/Volts.

To do any replacements of different bulbs you have to consider what the new current will be and if the wire size and fuse will be able to take the new current (amps). Use this formula, W = A x V or A = W/V.

There is no Roman numeral W. There is I, V, X, L, C, D and M but no W.

The 100W Bulb

100

I think it's a sports channel.

The 100-W bulb because it transforms electrical energy at a faster rate than a dimmer bulb.

40W Bulb will spiol due to over current passing through its coilAnswerSince the 40-W lamp has a higher resistance than the 100-W lamp, the greater voltage drop will appear the 40 W lamp. As a result the 40 W lamp will be subjected to a voltage beyond its 100-V rating, and the 100-W lamp will be subjected to a voltage below its 100-V rating. Therefore, the 40-W lamp will burn much more brightly than the 100-W lamp.Incidentally, the symbols for the 'watt' and 'volt' are upper, not lower, case: W and V.

Think the 100-watt?

The formula you are looking for is W = I x E. W = Amps x Volts.

100 W tungsten incandescent (220 V): 1380 lm

The formula you are looking for is I = W/E. Amps = Watts/Volts.

VW as in Volkswagen I suppose... The resistance of an incandescent(glow wire) bulb depends on the power - the wattage.

W= V x A or W/A=V