To determine the current required by a 75-W bulb in a 100-W circuit, we first need to know the voltage of the circuit. Assuming a standard voltage of 120 volts, the current can be calculated using the formula ( I = P/V ), where ( P ) is power in watts and ( V ) is voltage in volts. For a 75-W bulb, the current would be ( I = 75 , \text{W} / 120 , \text{V} = 0.625 , \text{A} ). Thus, the 75-W bulb requires approximately 0.625 amperes of current.
It depends on the wattage of the toaster. If the toaster has a wattage greater than 100W, then it will use more electricity than a 100W light bulb. If the toaster has a wattage less than 100W, then the light bulb will use more electricity.
Less than 0.02 watt/hours. Running your 100w bulb for an hour uses 100 watt/hours. The inrush current during the cold resistance of the bulb lasts for only a millisecond before the bulb is hot. This is insignificant on your electric bill even if you sat and flicked the lightswitch for the whole month, and is a common misconception that someone who didn't know what they were talking about made up.
The 100W bulb emits more light energy per second than the 40W bulb, so it appears brighter due to the higher intensity of light. This increase in brightness is a result of the higher power consumption and light output of the 100W bulb compared to the 40W bulb.
I = p/v = 100w/9v = 11.11ai = p*v = 100w*9v = 900ai = (p/2)*v = 50w*9v = 450ai = p*2*v = 100w*(9v + 9v) = 8100a
Let's examine what it means when a bulb is 100W rather than 60W. I'm assuming that you meant to state that they are 120V bulbs being connected to a 240V circuit1. With the same voltage on each, and because power is voltage times current, the current must be greater in a 100W bulb than in a 60W bulb. Since a incandescent bulb is a linear load, if you double the voltage then you double the current2. So the current through the 100W bulb is still greater than through the 60W bulb. Or you may analyze it a bit more. With both on 120V, for more current to flow in the 100W bulb, the resistance of it must be less than that of the 60W bulb. So you may generalize that under any voltage (same voltage applied to each), the 100W bulb will always have more current through it than the 60W bulb. 1Actually, if they are 120V bulbs in a 240V circuit, there is a high probability that they will blow out. But before they do, this is what will happen. 2Well, slightly less than double, because the temperature coefficient on the filament is positive, so the hotter it is, the greater the resistance. Although this may seem nonlinear, a light bulb or other temperature sensitive resistive element is still defined as linear if over the short term it obeys Ohms law at any instant of the waveform. The current in the 100 watt bulb will be greater. Power is current times voltage, so current is power divided by voltage. Voltage is the same is both cases of this question, so current is proportional to power at 240V.
Assume the rating of 100W refers to operation on a supply of 117 volts.Power = (voltage) x (current)Current = (power) / (voltage) = 100/117 = 0.855 ampere (rounded)Power = (voltage)2 / (resistance)Resistance = (voltage)2 / (power) = (117)2 / 100 = 136.89 ohms
It depends on the wattage of the toaster. If the toaster has a wattage greater than 100W, then it will use more electricity than a 100W light bulb. If the toaster has a wattage less than 100W, then the light bulb will use more electricity.
The 100W light bulb is brighter than the 60W light bulb. The difference in brightness is 40 watts.
Less than 0.02 watt/hours. Running your 100w bulb for an hour uses 100 watt/hours. The inrush current during the cold resistance of the bulb lasts for only a millisecond before the bulb is hot. This is insignificant on your electric bill even if you sat and flicked the lightswitch for the whole month, and is a common misconception that someone who didn't know what they were talking about made up.
A 100W incandescent light bulb typically produces around 1600 lumens of light.
The 100W bulb emits more light energy per second than the 40W bulb, so it appears brighter due to the higher intensity of light. This increase in brightness is a result of the higher power consumption and light output of the 100W bulb compared to the 40W bulb.
42 ohm
I = p/v = 100w/9v = 11.11ai = p*v = 100w*9v = 900ai = (p/2)*v = 50w*9v = 450ai = p*2*v = 100w*(9v + 9v) = 8100a
Let's examine what it means when a bulb is 100W rather than 60W. I'm assuming that you meant to state that they are 120V bulbs being connected to a 240V circuit1. With the same voltage on each, and because power is voltage times current, the current must be greater in a 100W bulb than in a 60W bulb. Since a incandescent bulb is a linear load, if you double the voltage then you double the current2. So the current through the 100W bulb is still greater than through the 60W bulb. Or you may analyze it a bit more. With both on 120V, for more current to flow in the 100W bulb, the resistance of it must be less than that of the 60W bulb. So you may generalize that under any voltage (same voltage applied to each), the 100W bulb will always have more current through it than the 60W bulb. 1Actually, if they are 120V bulbs in a 240V circuit, there is a high probability that they will blow out. But before they do, this is what will happen. 2Well, slightly less than double, because the temperature coefficient on the filament is positive, so the hotter it is, the greater the resistance. Although this may seem nonlinear, a light bulb or other temperature sensitive resistive element is still defined as linear if over the short term it obeys Ohms law at any instant of the waveform. The current in the 100 watt bulb will be greater. Power is current times voltage, so current is power divided by voltage. Voltage is the same is both cases of this question, so current is proportional to power at 240V.
The reading "100W-220V" on an electric bulb indicates that it is a 100-watt bulb designed to be used with a voltage of 220 volts. This information helps ensure that the bulb is used with the correct power supply to operate efficiently and safely.
Florescent tube
No. The heat from the larger bulb will damage the socket, and is a fire hazard.