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Let's examine what it means when a bulb is 100W rather than 60W.

I'm assuming that you meant to state that they are 120V bulbs being connected to a 240V circuit1.

With the same voltage on each, and because power is voltage times current, the current must be greater in a 100W bulb than in a 60W bulb.

Since a incandescent bulb is a linear load, if you double the voltage then you double the current2. So the current through the 100W bulb is still greater than through the 60W bulb.

Or you may analyze it a bit more. With both on 120V, for more current to flow in the 100W bulb, the resistance of it must be less than that of the 60W bulb. So you may generalize that under any voltage (same voltage applied to each), the 100W bulb will always have more current through it than the 60W bulb.

1Actually, if they are 120V bulbs in a 240V circuit, there is a high probability that they will blow out. But before they do, this is what will happen.

2Well, slightly less than double, because the temperature coefficient on the filament is positive, so the hotter it is, the greater the resistance. Although this may seem nonlinear, a light bulb or other temperature sensitive resistive element is still defined as linear if over the short term it obeys Ohms law at any instant of the waveform.

The current in the 100 watt bulb will be greater. Power is current times voltage, so current is power divided by voltage. Voltage is the same is both cases of this question, so current is proportional to power at 240V.

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