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When two bulbes with 25W and 100W rated at 220V are connected in series with a supply of 440V which will fuse?
The 25w bulb, since it has the much higher resistance. The resistance can be derived from:P = V^2/RR = V^2/PFor the 100w bulb:R = 220^2/100 = 484 ohmsFor the 25w bulb:R = 220^2/25 = 1936 ohmsWhen connected in series, and then connected to 440V, the voltage across the 100w bulb would be:V = 440*484/(484+1936) = 88VThis is well within spec.The voltage across the 25w bulb would be:V = 440*1936/(484+1936) = 352vThis is way over spec, and would cause the bulb to fuse.Although this answer assumes that a light bulb is a linear resistor, they are not. The resistance of a light bulb changes significantly with voltage and filiament temperature. The 25w light bulb is still the one that fuses, but the non-linearity of the resistance needs to be understood.
An electric bulb reads 220V-100W if it is connected across a 200V line what will be the power consumed?
80
If you put a 60W 120V bulb in a 120V lamp that has a transformer for 240V and plug it into a 240V outlet will it work or blow the circuitry?
Off hand no but your explanations are not clear as to who is doing what to whom,,
Two lamps A and B are rated 60W 220V and 100W 220V respectively so why does the answer say that when connected in parallal bulb A is brighter?
In parallel, they both obviously have 220 v across them, so the 100 W bulb is obviously brighter than the 60 W one. The 60 W bulb has more resistance, and in series they both have to pass the same current, so the 60 W has more voltage across it and might be brighter.
What seems to be making the light bulb turn on in your circuit?
The light bulb in the circuit turns on due to the flow of electric current, which is facilitated by a closed circuit. When the switch is closed, it completes the circuit, allowing electrons to move from the power source through the bulb, causing it to emit light. The resistance in the bulb converts electrical energy into light and heat, resulting in illumination.
What is the current being drawn by a 100W light bulb and what is the resistance of a 100W light bulb?
Assume the rating of 100W refers to operation on a supply of 117 volts.Power = (voltage) x (current)Current = (power) / (voltage) = 100/117 = 0.855 ampere (rounded)Power = (voltage)2 / (resistance)Resistance = (voltage)2 / (power) = (117)2 / 100 = 136.89 ohms
Can the resistance of a light bulb permanently change after it had been used for years?
240v is equal to how many amps
Which has a more resistance a 100 W bulb or a1000 W heater?
A 1000 W heater would have more resistance compared to a 100 W bulb. The higher the power rating of an electrical device, the lower its resistance, as resistance is inversely proportional to power. So, the 1000 W heater would have lower resistance than the 100 W bulb.
How much electricity use a light bulb -100W- in moment when you TURN ON the light switch?
Less than 0.02 watt/hours. Running your 100w bulb for an hour uses 100 watt/hours. The inrush current during the cold resistance of the bulb lasts for only a millisecond before the bulb is hot. This is insignificant on your electric bill even if you sat and flicked the lightswitch for the whole month, and is a common misconception that someone who didn't know what they were talking about made up.
Does a 100w light bulb use more electricity than a toaster?
It depends on the wattage of the toaster. If the toaster has a wattage greater than 100W, then it will use more electricity than a 100W light bulb. If the toaster has a wattage less than 100W, then the light bulb will use more electricity.
What is the difference in brightness between a 60W and 100W light bulb?
The 100W light bulb is brighter than the 60W light bulb. The difference in brightness is 40 watts.
How many lumens in a 100w light bulb?
A 100W incandescent light bulb typically produces around 1600 lumens of light.
How does the current in a light bulb connected to a 400 V source compare to the current when this light bulb is connected to a 60 V source?
Let's examine what it means when a bulb is 100W rather than 60W. I'm assuming that you meant to state that they are 120V bulbs being connected to a 240V circuit1. With the same voltage on each, and because power is voltage times current, the current must be greater in a 100W bulb than in a 60W bulb. Since a incandescent bulb is a linear load, if you double the voltage then you double the current2. So the current through the 100W bulb is still greater than through the 60W bulb. Or you may analyze it a bit more. With both on 120V, for more current to flow in the 100W bulb, the resistance of it must be less than that of the 60W bulb. So you may generalize that under any voltage (same voltage applied to each), the 100W bulb will always have more current through it than the 60W bulb. 1Actually, if they are 120V bulbs in a 240V circuit, there is a high probability that they will blow out. But before they do, this is what will happen. 2Well, slightly less than double, because the temperature coefficient on the filament is positive, so the hotter it is, the greater the resistance. Although this may seem nonlinear, a light bulb or other temperature sensitive resistive element is still defined as linear if over the short term it obeys Ohms law at any instant of the waveform. The current in the 100 watt bulb will be greater. Power is current times voltage, so current is power divided by voltage. Voltage is the same is both cases of this question, so current is proportional to power at 240V.
Why 100w bulb appears brighter than 40w bulb placed at same distance?
The 100W bulb emits more light energy per second than the 40W bulb, so it appears brighter due to the higher intensity of light. This increase in brightness is a result of the higher power consumption and light output of the 100W bulb compared to the 40W bulb.
How can you tell there is friction and resistance in a bulb?
Electrical resistance is technically not the same as friction though one could be used as a model for the other. Electrical resistance in a light bulb can be seen by the light that is emitted due to the heating of the filament when current is passed through it (electrical potential is transformed into heat).
When two bulbes with 25W and 100W rated at 220V are connected in series with a supply of 440V which will fuse?
The 25w bulb, since it has the much higher resistance. The resistance can be derived from:P = V^2/RR = V^2/PFor the 100w bulb:R = 220^2/100 = 484 ohmsFor the 25w bulb:R = 220^2/25 = 1936 ohmsWhen connected in series, and then connected to 440V, the voltage across the 100w bulb would be:V = 440*484/(484+1936) = 88VThis is well within spec.The voltage across the 25w bulb would be:V = 440*1936/(484+1936) = 352vThis is way over spec, and would cause the bulb to fuse.Although this answer assumes that a light bulb is a linear resistor, they are not. The resistance of a light bulb changes significantly with voltage and filiament temperature. The 25w light bulb is still the one that fuses, but the non-linearity of the resistance needs to be understood.
How much energy will a 100w light bulb convert to light and heat if it is left burning for 1hour?
Power = Energy/time 100W=Energy/360 Seconds Energy = 100/360 Energy ≈ 0.27 Joules
