The voltage across a resistance is in phase with the current through the resistance because the resitance in non-reactive, i.e. non-inductive and non-capacitative.
In the inductive case, the load resists a change in current. In the capacitative case, the load resists a change in voltage. In the resistive case, the load current follows the voltage with no delay, hence there is no phase differential.
It doesn't mean anything. Voltage and resistance cannot be described as being 'in phase'. It's only voltage and currentthat can be in phase, and this occurs in an AC purely-resistive circuit.
The amount of phase shift depends on the resistance that is also present in the system. In an ideal situation, the phase shift would be +90 degrees, but that would require a voltage source with zero resistance, conductors with zero resistance, and an ideal capacitor that exhibited only capacitance.
If the load current descrease, there is less voltage drop caused by the resistance of the wire, so the voltage is higher.
There is phase to phase voltage in 3 phase system.AnswerYou don't get voltage 'phase-to-phase'; it's 'line-to-line'!
The circuit becomes a pure resistance circuit where current and voltage are in phase with each others.
The formula to use is, phase voltage /1.73 = phase to neutral (ground) voltage.CommentThere is no such thing as a 'phase to phase', or 'phase to neutral' voltage. The correct terms are 'line to line' and 'line to neutral'. So the above answer should read: line voltage/1.73= line to neutral voltage = phase voltage.
in a circuit of pure Resistance (r), IE. voltage source (12 v DC battery) and pure resistance (a light bulb). the voltage (v) and current (i) will be in phase. by adding capacitors and/or inductors to the circuit V and I will be pulled out of phase.
a. the current and voltage in phase
First of all, there is no such thing as a 'phase-to-phase' voltage. The correct term is 'line-to-line' voltage. Secondly, without knowing what you mean by 'overall voltage', there is no way of answering your question.
If current and voltage of an AC are in phase, then the "power factor" is 100%, and the load is a pure resistance, with no inductive or capacitive reactance (at least at the operating frequency of the AC).
If the load current descrease, there is less voltage drop caused by the resistance of the wire, so the voltage is higher.
The amount of phase shift depends on the resistance that is also present in the system. In an ideal situation, the phase shift would be +90 degrees, but that would require a voltage source with zero resistance, conductors with zero resistance, and an ideal capacitor that exhibited only capacitance.
V=IR, voltage is directly propostional to current and resistance (by ohm's law).CommentVoltage is not 'proportional to resistance'. Resistance is a constant, and is not affected by voltage at all.
The phase angle between voltage and current in a purely inductive circuit, under ideal circumstances where there is no resistance at all, is 90 degrees.
There is phase to phase voltage in 3 phase system.AnswerYou don't get voltage 'phase-to-phase'; it's 'line-to-line'!
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)