Propene (C3H6) reacts with bromine (Br2) to form 1,2-dibromopropane when exposed to light. The addition of bromine to the double bond of propene causes the bromine atoms to be added across the double bond, resulting in a color change from orange to colorless as the reaction proceeds.
The IUPAC name for the organic compound that reacts with Br2 would depend on the specific compound in question. In general, the addition of bromine to an organic compound is called bromination.
To find the number of moles in 44.0 g of Br2, you need to divide the given mass by the molar mass of Br2. The molar mass of Br2 is approximately 159.808 g/mol. Therefore, 44.0 g Br2 is equal to 0.275 moles.
The equation 2K + Br2 -> 2KBr is balanced as there are equal numbers of atoms of each element on both sides of the reaction.
Propene has three carbon atoms.
When bromine reacts with propene, the double bond in propene breaks and bromine atoms add across the double bond, forming a dibromoalkane product. This reaction is a classic example of an addition reaction between an alkene and a halogen.
The IUPAC name for the organic compound that reacts with Br2 would depend on the specific compound in question. In general, the addition of bromine to an organic compound is called bromination.
Propene + Br2 + hv ==> 3-Bromo-1-propene (free radical halogenation - allylic position is halogenated only)3-bromo-1-propene + OsO4 ==> 1,2 dihydroxy-3-bromo propane (or, you can also use MCPBA to create the epoxide and open it with mild acid or base, or you can use Br2 and H2O to create the halohydrin... lots of options here)1,2 dihydroxy-3-bromo propane + NaOH ==> 1,2,3 trihydroxy propane (glycerin aka glycerol)
No the number of ATOMS in 1 Bomine MOLECULE Br2 is twice Avagadro's number.
Propane is C3H8.Propene is C3H6.
Propene has three carbon atoms.
To calculate the mass of 4.89 x 10^20 molecules of Br2, you need to use the molar mass of Br2, which is 159.808 g/mol. Calculate the number of moles of Br2: 4.89 x 10^20 molecules / 6.022 x 10^23 molecules/mol = 8.13 x 10^-4 moles Use the formula mass = moles x molar mass to find the mass: mass = 8.13 x 10^-4 moles x 159.808 g/mol ≈ 0.130 g
The empirical formula for propene (C3H6) is CH2. This is found by dividing the subscripts of each element by their greatest common factor, which in this case is 3.
When bromine reacts with propene, the double bond in propene breaks and bromine atoms add across the double bond, forming a dibromoalkane product. This reaction is a classic example of an addition reaction between an alkene and a halogen.
The formula for propene is C3H6. It is an unsaturated hydrocarbon with a double bond between two carbon atoms.
Propene is obtained from crude oil by cracking.
The major product from the treatment of propene with HCl is 2-chloropropane. The HCl adds across the double bond of propene to form a secondary alkyl halide.
There are 1 mole of atoms in 44.0 g of Br2. Since Br2 is a diatomic molecule, there are 2 moles of bromine atoms in one mole of Br2. Therefore, there are 2 moles of bromine atoms in 44.0 g of Br2.