They may be ethene, propene! ethyne, propyne and all the unsaturated hydrocarbons
I think it's dibromide..
1 mole Br2 = 159.808g Br2 = 6.022 x 1023 molecules Br2 4.89 x 1020 molecules Br2 x 1mol Br2/6.022 x 1023 molecules Br2 x 159.808g Br2/mol Br2 = 0.130g Br2
Sodium bromide reacts with chlorine to produce sodium chloride and bromine. 2NaBr + Cl2 --> 2NaCl + Br2. Bromine in color, though may appear yellowish in low concentrations.
You can add the sodium hydroxide solution(NaOH). Because NaOH reacts with Br2(Bromine) and generates NaBr. NaBr is dissolved in water while bromobenzene is layered with water, then you could remove Bromine by a liquid separation. The reaction is Br2 + 2NaOH = NaBr + NaBrO + H2O.
44.0 grams Br2 ? 44.0 grams Br2 (1 mole Br2/159.8 grams)(6.022 X 10^23/1 mole Br2)(1 mole Br2 atoms/6.022 X 10^23) = 0.275 moles of Br2 atoms
A bromoalkane may be obtained.
It is not an element, it's a compound. It would be called iron (II) bromide in the IUPAC system, or ferrous bromide in the antiquated pre-IUPAC nomenclature.
The chemical equation is:C2H2 + 2 Br2 = C2Br2H4
For chemistry, after IUPAC rules the standard temperature is 0 oC and the standard pressure is1 bar.
2KI+Br2 ---->2KBr +I2
It's Bromine.
Bromine replaces the iodide to form a Bromide.BaI2 + Br2 ----> BaBr2 + I2
Calcium react with bromine forming calcium bromide.
The chemical reaction is:2 HI + Br2 = 2 HBr + I2
Bromine, Br2
I think it's dibromide..
1 mole Br2 = 159.808g Br2 = 6.022 x 1023 molecules Br2 4.89 x 1020 molecules Br2 x 1mol Br2/6.022 x 1023 molecules Br2 x 159.808g Br2/mol Br2 = 0.130g Br2