A bromoalkane may be obtained.
Alkene + Cl2 or Br2 --> Adducts (addition products) dichloor alkane, dibroom alkane
Any number of chemical moieties could react with alkanes to produce new compounds in a substitution reaction. For example, hydrohalic acids (HCl, HBr, HI) could react with an alkane to produce a haloalkane. Here, the halogen atom would replace one of the hydrogen atoms in the alkane. (HCl + ethane --> chloroethane) (HBr + propane --> bromopropane) This also works with other reactive species, such as: - nitric acid + alkane --> nitroalkane
Sodium bromide reacts with chlorine to produce sodium chloride and bromine. 2NaBr + Cl2 --> 2NaCl + Br2. Bromine in color, though may appear yellowish in low concentrations.
Purple to colourless
I think that you can use the normal C==C test, ether Br2 water or I2 Br2 is probably the best though
The chemical equation is:2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2
The chemical equation is:C2H2 + 2 Br2 = C2Br2H4
Iron reacts with oxygen to produce rust.
2KI+Br2 ---->2KBr +I2
They may be ethene, propene! ethyne, propyne and all the unsaturated hydrocarbons
Bromine, Br2, reacts with water to produce hypobromite, OBr-. The position of the equilibrium depends very much upon the pH of the solution. Br2(l) + H2O(l) ⇌ OBr-(aq) + 2H+(aq) + Br-(aq)
Bromine replaces the iodide to form a Bromide.BaI2 + Br2 ----> BaBr2 + I2