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Q: What electron configurations end with d2 electrons?
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yes an electron can be found in a circular orbit as (Y-X2) can be made to form rocket fuel (D2-S), there for, it is highly possible.


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Here~ D2 D2 D2 B D2 C2 B A C2 C2 C2 A C2 B A G D2 D2 D2 G G A B C2 C2 C2 C2 D2 C2 B A G D2 D2 D2 B D2 D2 D2 B D2 D2 D2 E2 D2 D2 B C2 C2 C2 A C2 C2 C2 A C2 C2 C2 B2 C2 B A G


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Atoms of elements with the same electron configuration are organized in in the Periodic Table?

They are not! It is a prevalent myth that the elements are organized so that elements with the same configuration are organized into the same group, but all that really matters is the number of valence electrons, and that much is guaranteed by the arrangement in order of atomic number.So we have for example in group 10, Ni with configuration [Ar] 3d8 4s2 , Pd with configuration [Kr] 4d10 , and Pt with configuration [Xe] 4f14 5d9 6s1.Group 4 is characterized (supposedly) by the electron configuration d2 s2 but thorium which has this configuration is not placed in this group but in the actinides.


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In order to get through the fireflower maze on Lava, make sure you are on foot! Riding your horse through the flowers will not work! Follow the guide below, the numbers are for how many steps you take, make sure to count carefully or you'll end up back at the beginning! Good luck! d2 r4 u2 l1 u2 r4 d2 r1 d1 r2 u3 r5 d2 l2 d2 r7 u2 l2 u3 r7 d2 r5 d2 r2 u2 r15 d5 l2 d1 l2


How many liters of water in a rectangular swimming pool 5.7 meters by 3 meters which is 1.1 meters at the shallow end and 1.7 meters at the deep end?

assume:Length = L = 5.7 mWidth = W = 3.0 mDepth 1 = D1 = 1.7 mDepth 2 = D2 = 1.1 mVolume = L x W x D2 + 1/2 [ L x W x (D1 - D2)]= L x W x [ D2 + 1/2 D1 - 1/2 D2]= L x W x [D1 +D2] /2= 5.7 x 3.0 x [1.7 + 1.1]/2= 23.94 cubic meter1 cubic meter = 1000 literVolume = 23.94 x 1000 = 23940 liter


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