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Q: What element do most of the polytamic ions have in the formula?
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What element do most of the polyatomic ions have in the formula?

Examples: oxygen, sulfur, carbon, phosphorus etc.


What element do most polyatomic ions contain?

Oxygen


What element is most likely to form ions with -3?

Phosphorous or nitrogen


In a formula for an ionic compound which element comes first?

The more or most electropositve element.


What is th formula for a weak base?

There is no such formula, but most bases are weak except hydroxyl ions OH- and some uncommon ones.


How do you know which element comes first in a molecular formula?

The more or most electropositve element comes first.


What element is in most common liquid whose formula is L2Br?

oxygen


Which particle most affects which group an element is in?

Try "the proton" (change the electrons and you get ions, change the neutrons and you get an isotope.)


How many moles of ammonium ions are in 8.903 g of ammonium carbonate?

The most common form of solid ammonium carbonate is a hydrate with formula (NH4)2CO3.H2O and a gram formula unit mass of 114.10. The formula shows that each formula unit contains 2 ammonium ions. The number of formula units of ammonium carbonate is 8.903/114.10 or 0.078028. The number of formula units of ammonium ions is twice this, or 0.1561, to the justified number of significant digits.


Which polyatomic ion has 4 oxygens?

The three most common such ions probably are sulfate, with the formula SO4-2, chromate, with the formula CrO4-1, and perchlorate, with the formula ClO4-1.


What is the expected formula of a compound formed from the ions M plus 3 and X 1?

Most likely, MX3


How many ammonium ions are present in 10.7g of ammonium phosphate?

The formula for the most common form of ammonium phosphate is (NH4)3PO4.3 H2O, and its gram formula mass is 203.13. The formula shows that there are 3 ammonium ions in each formula unit. 10.7g/203.13 is 5.27 X 10-2 formula units. Therefore, the number of ammonium ions present in 10.7g of this ammonium phosphate is 3 X 5.27 X 10-2 X Avogadro's Number or 9.52 X 1019 ammonium ions, to the justified number of significant digits.