First, make sure you got the right products because if not, it may be impossible to balance. Next, try to count multi-elemental ions such as SO4^-2 as one ion. Then, look at the unique elements that most problems do not see and only appear in one product and reactant. After you balance the "unique" elements, then double check to see if your hydrogens and oxygens are balanced as well. If the equation is simple, they should balance automatically.
When balancing chemical equations, it's best to start with the compound or molecule that is the most complex. Here's an example: C2H6 + O2 --> CO2 + H2O I would start with the compound, C2H6, which is on the reactant side of the equation. I chose C2H6 (ethane) because it not only has multiple types of atoms, but it also contains a large amount of those atoms, compared to any other compound or molecule within the equation. You should leave any elements in their elemental form for last (such as O2). The Solution: Work with the C2H6 molecule has your guide. STEP 1: There are 2 carbons in C2H6, so we need to place a 2 in front of the CO2 as follows: C2H6 + O2 --> 2CO2 + H2O
STEP 2: There are 6 hydrogens in C2H6, thus we need 6 hydrogens on the products side. Place a 3 in front of the H20. There are now 6 hydrogens, as well as 3 oxygens atoms. C2H6 + O2 --> 2CO2 + 3H2O
STEP 3: We now have the most complex molecule accounted for and, we have balanced all the carbon and hydrogen molecules. However, we need to draw our attention to the oxygen atoms. We can fix this by placing 3.5 in front of the O2 (on the reactant side). C2H6 + 3.5O2 --> 2CO2 + 3H2O
STEP 4: The equation is technically balanced, however, you cannot have halves of molecules. In this case, you cannot have three and a half O2 molecules. To fix this, we can now multiply the entire equation by the 2. This doubles the number of all products and reactants, but more importantly, everything is now in whole number ratios. The final balanced chemical equation looks like this: 2C2H6 + 7O2 --> 4CO2 + 6H2O
See there is no rule to look at a specific element.
For example, in the following equation:
Mg+Cl = MgCl2
==Mg+2Cl = MgCl2
Here we see both sides and then decide which element has to be numbered.
Start by balancing the atoms of elements that appear in only one reactant and one product. Typically, balance elements in compounds before balancing individual atoms by using coefficients.
* H2O+CO2 ---> H2CO3 Since Water is neutral we can look at methods of extracting the CO2 first.
Ignore hydrogens or oxygens...they can be easily balanced at the end. Balance the carbons first
you do it all at the same time
Check the total number of atoms for each element. When balanced, there will be the same number of atoms for each element on each side of the equation. If this is already the case, no balancing is required.If the number is not the same, the first balancing to be done is for the most complex molecules, the ones with the most elements and the most atoms of each element. These will ordinarily be the hardest to balance, and it is easier to change the simpler molecules, and the single elements, once these are done.
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O
GO to Google.com and type in balancing chemical equations and click the 3rd one. It balances it for you. Just type in the formula. :]
if u want to gate Ur answer than u first u have to know about molecular formula and balance it with the number of atoms of the elements
There should be seven in the second shell and two in the first. The element in question is fluorine, which has the atomic number 9, the same as the number of its protons and electrons.
Whatever you want. You can start with whichever element that isn't balanced
The first step in solving a stoichiometry problem is to balance the chemical equation to ensure the number of atoms of each element is the same on both sides.
Jean Beguin was the first iatrochemist to balance a chemical equation.
balance the equation. calculate moles of product.
Some additional factors to consider when balancing equations include ensuring the charges are balanced, verifying that the chemical formulas are correctly written, incorporating any coefficients needed to balance the equation, and confirming that the reaction obeys the law of conservation of mass.
An equation is balanced if each atom on one side of the arrow has the exact same amount on the other side. You can balance the equation by adding coefficents in front of the element, but make sure there are the same amount. For example: if you have 3 atoms of Al on the left of the arrow, and 6 atoms of Al on the right side, all you have to do is add the number 2 as a coefficient in front of the first Al to make 6 atoms of Aluminum on each side.
First write down what you know. Reactants go on the left, followed by an arrow, with products on the right. Balance the equation.
To balance the equation KOH + H3PO4 → K3PO4 + H2O, first write out the unbalanced equation. Next, balance the number of atoms of each element on both sides of the equation by adjusting the coefficients in front of each compound. In this case, you would need to put a coefficient of 3 in front of KOH, 1 in front of H3PO4, 1 in front of K3PO4, and 3 in front of H2O to balance the equation.
Rotate and balance, then alignment.
To balance any chemical equation, first ensure that you have the correct formulae for all the reactants and products:BaCl2 + H2SO4 ------> BaSO4 + HClThen work methodically through the equation, making sure that there are the same numbers of each element present on either side of the equation.In this case, we need an extra chlorine on the right hand side, and an extra hydrogen on the RHS, so the result?BaCl2 + H2SO4 -------> BaSO4 + 2HCl
Check the total number of atoms for each element. When balanced, there will be the same number of atoms for each element on each side of the equation. If this is already the case, no balancing is required.If the number is not the same, the first balancing to be done is for the most complex molecules, the ones with the most elements and the most atoms of each element. These will ordinarily be the hardest to balance, and it is easier to change the simpler molecules, and the single elements, once these are done.
Check the total number of atoms for each element. When balanced, there will be the same number of atoms for each element on each side of the equation. If this is already the case, no balancing is required.If the number is not the same, the first balancing to be done is for the most complex molecules, the ones with the most elements and the most atoms of each element. These will ordinarily be the hardest to balance, and it is easier to change the simpler molecules, and the single elements, once these are done.