3 volt bulb gives the biggest resistance
V = IR Voltage = Current * Resistance so 9 = 0.25 * R Hence R =36 Ohms
yes
Yes. A 60W bulb has a higher resistance than the 40W buld. The extra resistance requires more current to light up the bulb. The fillament then glows brighter.
Volt (V) = Resistance (R) times Current (I) therefor R = V / I 30 Ω = 3V / 0.1A
The bulb with the lowest resistance. Current = Volts / Resistance
Can you use a 120 volt bulb in a 130 volt socket?
If you want your bulbs to last longer then use 130 volt bulb on a 120 volt system. The light emitted by a 130 volt bulb, when comparing it to a 120 volt bulb, will be a bit dimmer.
The current depends on the total effecvtive resistance of everything connectedacross the battery.If the bulb is the only component there, then the current is E/R = 9/12 = 0.75 amperes.
There is a 3.75 Volt drop across each bulb.
Yes. The resistance of a globe depends not only on the wattage of it but also on the voltage. A 12 V Globe would has a quarter the resistance of a 24 volt globe for the same wattage. (when alight)
That depends on what voltage it's designed to operate from. Power = (voltage)2 / R R = Voltage2 / power If it's a 117-volt bulb, R = (117)2 / 28 = 489 ohms. If it's a 240-volt bulb, R = (240)2 / 28 = 2,057 ohms.
On this calculation I am assuming that the light bulb is using a 120 volt source. Watts = Amps x Volts. Amps = Watts/Volts, 40/120 = .33 amps. R = Volts/Amps, 120/.33 = 363.6 ohms resistance in the 40 watt light bulb.