That depends on what voltage it's designed to operate from.
Power = (voltage)2 / R
R = Voltage2 / power
If it's a 117-volt bulb, R = (117)2 / 28 = 489 ohms.
If it's a 240-volt bulb, R = (240)2 / 28 = 2,057 ohms.
On this calculation I am assuming that the light bulb is using a 120 volt source. Watts = Amps x Volts. Amps = Watts/Volts, 40/120 = .33 amps. R = Volts/Amps, 120/.33 = 363.6 ohms resistance in the 40 watt light bulb.
To calculate the resistance of a 5 watt light bulb, you can use the formula P = V^2 / R, where P is power (5 watts) and V is voltage (typically around 120V for a household light bulb). Rearranging the formula to solve for resistance, you get R = V^2 / P. Plugging in the values, R = (120V)^2 / 5W = 2880 ohms. So, a 5 watt light bulb at 120V would have a resistance of 2880 ohms.
The main difference between a 100-watt and a 75-watt light bulb is the amount of light output they produce. A 100-watt bulb will be brighter and consume more energy compared to a 75-watt bulb. The 100-watt bulb may also generate more heat than the 75-watt bulb.
A 75 watt bulb produces about 75 watts of heat.
The lumen output of a 150 watt bulb can vary depending on the type of bulb. However, as a general guideline, a 150 watt incandescent bulb typically produces around 2600-2800 lumens.
No, the highest wattage bulb will have the lowest resistance.
The resistance of a light bulb varies, depending on the type of bulb, the power rating, and the temperature. A typical incandescent 60 watt bulb, for instance has a cold resistance of about 30 ohms, and a hot resistance of about 240 ohms.
It means exactly what it sounds like. The resistance of an incandescent bulb's filament depends on its temperature. A filament has a positive temperature coefficient, which means that its resistance increases as its temperature increases. A typical 40 watt bulb (120 volts) has a cold resistance of about 28 ohms, but its hot, operating resistance is about 360 ohms. If the cold resistance were constant, the bulb would dissipate 379 watts. In fact, cold turn on is the most stressful time for a bulb.
A halogen bulb IS ITSELF a type of incandescent illumination source. A 40 Watt traditional incandescent bulb usually emits about 400 to 500 lumens while a halogen may emit close to twice that. So a 25 W halogen might give out as much light as ah older style 40 W bulb.
As per the formula for power (Power (Watt) = Voltage (V) x Current (i) & Resistance (R) = V / i), 25w lamp bulb would have higher resistance compared to that of 5w lamp bulb.
On this calculation I am assuming that the light bulb is using a 120 volt source. Watts = Amps x Volts. Amps = Watts/Volts, 40/120 = .33 amps. R = Volts/Amps, 120/.33 = 363.6 ohms resistance in the 40 watt light bulb.
To calculate the resistance of a 5 watt light bulb, you can use the formula P = V^2 / R, where P is power (5 watts) and V is voltage (typically around 120V for a household light bulb). Rearranging the formula to solve for resistance, you get R = V^2 / P. Plugging in the values, R = (120V)^2 / 5W = 2880 ohms. So, a 5 watt light bulb at 120V would have a resistance of 2880 ohms.
No. A 70 Watt metal halide bulb can not be replaced with a 150 Watt halide bulb.
Yes. A 60W bulb has a higher resistance than the 40W buld. The extra resistance requires more current to light up the bulb. The fillament then glows brighter.
The resistance of the bulbs doesn't depend on the voltage source. They can be wrapped in tissue in cardboard boxes in the drawer. If one bulb is designed to dissipate 200 watts and another is designed to dissipate 600 watts when they're both energized by the same voltage, whatever that is, then the 200-watt bulb has three times the resistance of the 600-watter.
A 100 watt 220 volt light bulb (or anything consuming 100 watts on 220 volts) draws 100/220, or .45 Amps. It will also have about 220²/100, or 484 ohms resistance. A 60 watt 220 volt light bulb (or anything consuming 60 watts on 220 volts) draws 60/220, or .27 Amps. It will also have about 220²/60, or 807 ohms resistance.
A 13-15 watt compact fluorescent bulb (CFL) or a 9-11 watt LED bulb is roughly equivalent to a 60 watt incandescent bulb in terms of light output.