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What happen to the parallel circuit if one resistance is removed?
Wiki User
∙ 12y ago
assume the following configuration: battery connected to 2 parallel resistors with an ammeter in series with the battery... observe the current measurement ... remove one of the resistors .... observe the current again, it will have decreased: if the resistors were of equal value, the current will decrease to half of its original value when one of the resistors is removed. Mathematics:
V=IR (V- voltage, I - current, R - resistance
in a parallel circuit, R=(R1*R2)/(R1+R2) where R1 and R2 are the values of resistance of the resistors. Before removal- Ib=V*(R1+R2)/(R1*R2)
After removal (assume R2 is removed)- Ia=V/R1
so Ia/Ib=(R1*R2)/(R1*(R1+R2))
or Ia=Ib*(R2/(R1+R2)
if R1=R2 then Ia=Ib*R2/(2*R2) or Ia=Ib/2 so the current after is 1/2 of that before.
Wiki User
∙ 12y ago
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In what sense.
What will happen if a second bulb is added to a parallel circuit?
-- The voltage doesn't change. -- If the second light bulb is identical to the first, then the total resistance drops by half. -- If they're not identical, then we have to know the details of both before we can calculate their combined effective resistance.
What happen if you change the position of ammeter in the circuit in parallel and series?
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What will happen to a buzzer connected to a circuit?
If it is connected in series with a circuit then it might raise the resistance too high and fail the system. Parallel connection is a circuit is probably the best bet you have.
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There will be no change, because it is a parallel circuit.
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What will happen to voltage in a parallel circuit?
In a parallel circuit the voltage across each component is the same.
What happen to the circuit if there is higher resistance?
In what sense.
Which uses more energy parallel circuit or a series circuit?
That depends. For example, if the circuit is consisted of two resistors, 2 ohms each, the equivalent resistance (Req) of these two resistors in series is 4 ohms, and the Req of these two resistors in parallel is 1 ohm. If the same voltage is applied, say 4 V.power consumed in a resistance = V2/R.The parallel circuit: Power = 4 * 4 / 1 = 16 [W].The series circuit: Power = 4 * 4 / 4 = 4 [W].With everything else the same, a parallel circuit consumes more energy than a series circuit.Note that circuits of only simple resistors are discussed. You need to consider each circuit on its merit.================================AnswerIt depends. In both cases, the total energy expended will be the sum of the energies expended by each individual load.
What will happen if you undo a bulb in a parallel circuit?
The bulb you remove will go out :) Overall current will also be reduced proportional to the resistance of the bulb being removed. Lets say you have two 60 W incandescent bulbs in parallel and they each are drawing 1/2 Amp (60W = 120 Volts x 1/2 Amp). The resistance of each bulb is 240 Ohms (120 Volts / .5 Amps). The parallel resistance is 120 Ohms so 1 Amp is being drawn. When one of the two bulbs is removed the resistance changes from 120 Ohms to 240 Ohms, reducing the current from 1 Amp to 1/2 Amp.
What will happen if ammeter is put across a resistance in a circuit?
Maybe blow the fuse or burn out the wiring. An ammeter has an extremely low resistance. connecting it across the resistance causes the resulting parallel resistance to be slightly lower than the resistance of the ammeter 1/Rt = 1/R + 1/R(ammeter)
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If the resistance increases, while the voltage stays the same, current will decrease. Current = voltage divided by resistance
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It wil be on
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