Balanced equation formed:
H2SO4 + 2KBr ==> 2HBr + K2SO4
2 HCOONa + H2SO4 → 2 CO + 2 H2O + Na2SO4
React benzene with conc. H2SO4 and then with conc. HNO3. The resultant would be picric acid
Concentrated sulphuric acid. It is H2SO4 in a concentration of probably 6M or above.
3h2so4+fe203------>fe2(H2So4)3 + H20 conc.
it gives off chlorine gas, the acid needs to be conc. though what the hell is to be conc. im not a nerd so can some one explain to me plesh
lABORATORY METHOD:Nitric acid can be prepared in he laboratory by the action of the conc. h2so4 on the potassium nitrate
You use concentrated phosphoric or sulfuric acid at high temperatures in order to dehydrate it and eliminate the OH group. Therefore, conc. H3PO4 or conc. H2SO4 at 300 ˚C.
h2so4 being good oxidising agent oxidises the h2s to h2o and free sulphur.so conc h2so4 cant be used in preparation of h2s gas
Mixture of Conc. nitric acid and Conc. Sulphuric acid
Assuming the conc. H2SO4 is 18 M (or close to it), then use V1M1 = V2M2 and to make, say 1 liter,(x ml)(18 M) = (1000 ml)(0.1 M) and x = 5.56 mls of conc. H2SO4 diluted to a final volume of 1 liter to make 0.1 M.
KAt + H2SO4(conc) = KHSO4 + HAt displacement then .......HAt + .......H2SO4 = At2 + H2S which can be balanced as follows: 2At- = At2 + 2e ] * 4 8e + 8H+ + H2SO4 = H2S + 4H2O overall is 8At- + 8H+ + H2SO4 = H2S + 4H2O + 4At2
FOLLOW THIS FORMULA: N1V1=N2V2 36*V1=6*1000 V1=6000/36 =166ml from conc. H2SO4
first make 10N solution by addind 27.7ml conc H2So4 in 73.3ml water then take 1 ml from 10N and add 999ml water
0.2% of anthrone was dissolved in 100ml of conc H2SO4.
You standardize it by titrating it with another standardized base.
You drop conc. HCl into conc. H2SO4 - this releases HCl gas which you can bubble through dry ether... Or, you use an HCl cylinder.
suppose you have conc. sulfuric acid 96% sp.gr 1.84 so 1.25% sulfuric equal to 1/96*100=1.3 1.3ml of conc. sulfuric per 100ml water so 13 ml per liter
Hydrogen cyanide (HCN) is most likely the gas evolved.
Diethyl ether can be formed from alcohol by intermolecular dehydration of alcohols. When alcohol is heated with conc. H2SO4 at 140*C, diethyl ether is obtained. CH3CH2OH + H2SO4 -----------> CH3CH2OCH2CH3 ( diethyl ether) It must be noted that at high temp (180*C) the reaction is elimination which form alkene.
nitric acid is light sensitve , it decomposes when expose in light. when aluminium is added to the conc HNO3 it remain passive in conc nitric acid,...... and moreover aluminium oxide layer is also form due to which it remain passive in conc nitric acid...
No reaction; you can obtain only an acid mixture.