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In the circuit where the DC motor is added, it was not specified whether the motor was added in series or in parallel to circuit elements. If it was added in series, it will increase circuit resistance and it will cause circuit current to go down. In parallel, the motor will reduce total circuit resistance, and circuit current will increase.
The reduction of voltage or the increase of resistance will reduce the current in a circuit.
The total resistance of the circuit increases. hence the new resistance after adding the resistance will be new resistance = old resistance + added Resistance There is a small mistake in the question. The second word is 'changes' not 'charges'
The total current decreases.According to the Ohm's law the current & the resistance are inversely proportional so when we put a load in series with the existing load, the resistance of the circuit increases therefor the current decreases.
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
extra resistance is added in order to decrease starting current and improve starting torque
The resistance is increased, the voltage across each bulb is decreased and the current through the circuit is reduced.
"http://www.tpub.com/neets/book1/chapter3/1-26.htm" This site explains how to calculate the resistance, but it decreases the resistance when you add more.
Adding anything(yes,even a superconductor) to a any circuit adds resistance, especially devices that are by there very nature high resistors
You raise the total resistance by that amount if added in series to a circuit. If you add them in parallel to a circuit then that total resistance will be less than the total of the added circuit.
In the circuit where the DC motor is added, it was not specified whether the motor was added in series or in parallel to circuit elements. If it was added in series, it will increase circuit resistance and it will cause circuit current to go down. In parallel, the motor will reduce total circuit resistance, and circuit current will increase.
When you have multiple loads in a series, the resistance of the loads is added together allowing very little current to flow through the circuit to power any of the loads, making for a low amperage circuit. If you have your loads in parellel, the resistance of the loads in the circuit is subtracted which allows more current to flow, making for a high amperage circuit.
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The reduction of voltage or the increase of resistance will reduce the current in a circuit.
When you have multiple loads in a series, the resistance of the loads is added together allowing very little current to flow through the circuit to power any of the loads, making for a low amperage circuit. If you have your loads in parellel, the resistance of the loads in the circuit is subtracted which allows more current to flow, making for a high amperage circuit.
The total resistance of the circuit increases. hence the new resistance after adding the resistance will be new resistance = old resistance + added Resistance There is a small mistake in the question. The second word is 'changes' not 'charges'
No. The resistance in a series circuit is all the resistor values added together. eg. If two resistors were in a circuit, one was 10 ohms and the other was 30 ohms, the resistance in the circuit would be 30 ohms. Hope this helps!