there would be no problem with this == == The inductive circuit has a 'lagging' power factor. If you over-compensate with too much capacitive reactance, you could go over the top (past 1.0) , and end up with a leading power factor that may even be numerically worse than when you started.
== == == ==
An inductive filter is in fact an LC circuit in which an inductor is connected in series with the capacitor. This arrangement is also known as a low-pass filter. http://www.answers.com/topic/inductive-filter
There's no effect since the capacitor was already faulty i.e it was like not in the circuit. Install a healthy capacitor because it will improve the power factor of the fluorescent lamp circuit thus reducing energy wasted.
A small capacitor can be part of an integrated circuit.
An ideal inductor only has inductance. And ideal resistor only has resistance. And an ideal capacitor only has capacitance. In real life, however, all 3 have some amount of the characteristics of the others. So, in an inductive or capacitive circuit you should only have apparent power in theory, but in an actual circuit you will have resistance from the inductor or capacitor and from the conductors that connect them. This resistance is where the true power is dissipated.
What happens to the current in a circuit as a capacitor charges depends on the circuit. As a capacitor charges, the voltage drop across it increases. In a typical circuit with a constant voltage source and a resistor charging the capacitor, then the current in the circuit will decrease logarithmically over time as the capacitor charges, with the end result that the current is zero, and the voltage across the capacitor is the same as the voltage source.
Inductive. Voltage (E) leads current (I) in an inductive (L) circuit and current (I) leads voltage (E) in a capacitive (C) circuit. (ELI the ICEman)
You want a power factor of 1 or 100%, which is a purely resistive circuit. If you have a motor or some other inductive load in a circuit the total voltage and total current in the circuit will not be in phase (phase shift), your power factor will be less than 1. By adding a capacitor (180 degrees out of phase with inductive load) to the circuit that has a capacitive reactance equal to the inductive reactance of the motor, you can cancel the phase shift and have an ideal power factor (no wasted power). Anything above .9 would be good.
In general the length of the leads contributes only a negligible amount to the capacitance of a capacitor. However at high enough frequencies excessive lead length can contribute an undesirable amount of parasitic inductive reactance, causing problems in circuit operation.
Any circuit using a capacitor will not work if the cap is short-circuited.
You would use a supply bypass capacitor in a common collector amplifier... It's necessary, to give the positive supply rail a direct AC connection to ground. Without it, I don't think the amplifier would work properly. However, if you're using a power supply and not a battery, then chances are that it HAS a big capacitor inside it, eliminating the need for any external capacitor.
paper capacitor
when we replace the resistor with a capacitor ,the current will flow until the capacitor charge when capacitor will fully charged there is no current through the circuit because now capacitor will act like an open circuit. for more info plz E-mailt me at "zaib.zafar@yahoo.com"