Capacity to the equivalent of the battery is reduced - that is, you'll run out of charge quicker but the voltage delivered will still be the same.
12V. Every resistor in a parallel circuit shares the same voltage. It is the current that gets divided.
if we remove a resistor from the parallel connection the effective resistance value will be increased.
Nothing. All the light bulbs in your house are connected in parallel. In a parallel circuit the same voltage appears across all the loads, and the supply voltage is nearly constant, so if one bulb is switched off it makes no difference to the others.
assume the following configuration: battery connected to 2 parallel resistors with an ammeter in series with the battery... observe the current measurement ... remove one of the resistors .... observe the current again, it will have decreased: if the resistors were of equal value, the current will decrease to half of its original value when one of the resistors is removed. Mathematics: V=IR (V- voltage, I - current, R - resistance in a parallel circuit, R=(R1*R2)/(R1+R2) where R1 and R2 are the values of resistance of the resistors. Before removal- Ib=V*(R1+R2)/(R1*R2) After removal (assume R2 is removed)- Ia=V/R1 so Ia/Ib=(R1*R2)/(R1*(R1+R2)) or Ia=Ib*(R2/(R1+R2) if R1=R2 then Ia=Ib*R2/(2*R2) or Ia=Ib/2 so the current after is 1/2 of that before.
By connecting it to a circuit with the power still applied. Ohm meters work best when the component under test is removed from the circuit to eliminate parallel paths of current through other components.
The battery cannot be removed quickly! Inductance of the wiring stores energy and keeps the current flowing and decaying smoothly. There will be an opposite polarity, higher voltage pulse on the battery terminals, limited by the circuit capacitance only.
Because circuit don't break unlike in series.That means rest of the component are getting the voltage across them.
The battery cannot be removed quickly! Inductance of the wiring stores energy and keeps the current flowing and decaying smoothly. There will be an opposite polarity, higher voltage pulse on the battery terminals, limited by the circuit capacitance only.
Current will go up by a factor of 6 times in that scenario.
Current will go up by a factor of 6 times in that scenario.
If you are referring to an electrical circuit, a series circuit is wired in such a way that if one object is removed from the circuit, the circuit is broken and everything within the circuit loses power. In a parallel circuit different components of the circuit can be removed without disabling power to the rest of the devices within the circuit.
It wil be on
it won't flow
No, the total resistance increases.
12V. Every resistor in a parallel circuit shares the same voltage. It is the current that gets divided.
if we remove a resistor from the parallel connection the effective resistance value will be increased.
Nothing. All the light bulbs in your house are connected in parallel. In a parallel circuit the same voltage appears across all the loads, and the supply voltage is nearly constant, so if one bulb is switched off it makes no difference to the others.