When HCl and NaOH react common salt (NaCl) is formed .This reaction is also called neutralization reaction .
Saonification happens when a fatty acid is reacted with NaOH.
ester+ NaOH
Increase
NaOH and HCl
The product is sodium chloride.The reaction is:NaOH + HCl - NaCl + H2O
Saonification happens when a fatty acid is reacted with NaOH.
ester+ NaOH
Increase
NaOH and HCl
The product is sodium chloride.The reaction is:NaOH + HCl - NaCl + H2O
First of all, it is HCl solution, more properly hydrochloric acid (that is HC l ). It is composed of hydrogen (H) and chlorine (Cl). The answer depends on the volume of the acid and the concentration of the alkali. Here is a sample calculation with some random values for the variables you have not given. If the HCl is neutralized by 25.0 ml of 0.500 M NaOH, then the number of moles of NaOH equals the number of moles of HCl. 25 ml is equal to 0.025 liters, and since molarity is moles per liter we have: Moles of NaOH = 0.0250 Liters * 0.500 moles/liter = 0.0125 moles Moles of NaOH = moles of HCl = 0.0125 moles If there are 0.0125 moles HCl in 45.0 ml (or 0.045 L), then the molarity of the HCl is: 0.0125 moles ÷ 0.0450 L = 0.278 moles/L = 0.278 M HCl
HCl is an acid which reacts with NaOH a base to produce H2O water and a salt - in this case NaCl HCl + NaOH = NaCl + H2O
HCl + NaOH -----> NaCl + H2O
No. of mol of NaOH used = 30/1000 x 0.125 = 0.00375No. of mol of HCl used = 25/1000 x 0.15 = 0.00375No. of mol of HCl used = No. of mol of NaOH used.Hence, the resultant solution will be neutral. pH ~ 7.(NaCl formed is a neutral salt, does not undergo any form of salt hydrolysis)
The reactants are NaCl and H2O. A becks: HCl NaOH
The reactants are HCl and NaOH.
Balanced equation. NaOH + HCl -> NaCl + H2O all one to one. find moles HCl. 11 grams HCl (1 mole HCl/36.458 grams ) = 0.3017 moles HCl Moles HCl same as moles NaOH Molarity = moles of solute/Liters of solution 1.06 M NaOH = 0.3017 moles NaOH/liters of solution = 0.2846 Liters this is equal to..... 285 milliliters of NaOH needed