Oxygen, in its ground state, has 6 electrons in its outer most shell. In order to be like a noble gas, it needs 2 more, so it will gain 2 electrons to be O^2-. It can then form an ionic bond with a metal, such as Na, which will lose an electron (2 sodium atoms) to make Na2O (sodium oxide).
The element that forms an ion with an electronic configuration of Ar with a -2 charge is oxygen (O). When oxygen gains two electrons, it achieves a stable electron configuration similar to argon.
It accepts one electron.
The element is platinum (Pt). It has the electron configuration [Xe]4f145d96s1. By losing three electrons from the 6d orbital, it forms a 3+ ion with the electron configuration [Xe]4f145d6, which corresponds to Kr4d6 electron configuration.
The He+ ion (helium ion) has the same electron configuration as an atom of helium (He) because it has lost one electron, making it a 1+ ion. Both the helium atom and He+ ion have a total of 2 electrons arranged in the 1s orbital.
study island answer- It gives up two electrons
It accepts one electron.
It accepts one electron.
It accepts one electron.
The He+ ion (helium ion) has the same electron configuration as an atom of helium (He) because it has lost one electron, making it a 1+ ion. Both the helium atom and He+ ion have a total of 2 electrons arranged in the 1s orbital.
study island answer- It gives up two electrons
Argon
A fluorine atom gains one atom in order to achieve the same electron configuration as neon. In doing so, the fluorine atom forms a fluoride ion with a 1- charge with the formula F-. As a negatively charged ion, it can form ionic bonds with various positively charged ions.
Oxygen
Chlorine forms a negative ion by gaining one electron to achieve a stable electron configuration with a full outer shell. This results in the formation of a chloride ion, which has a negative charge.
Alkali metals and alkaline earth metals will form ions (by losing 1 and 2 electrons respectively) with noble gas electron configuration.
The element is platinum (Pt). It has the electron configuration [Xe]4f145d96s1. By losing three electrons from the 6d orbital, it forms a 3+ ion with the electron configuration [Xe]4f145d6, which corresponds to Kr4d6 electron configuration.
Chlorine (Cl)