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Oxygen, in its ground state, has 6 electrons in its outer most shell. In order to be like a noble gas, it needs 2 more, so it will gain 2 electrons to be O^2-. It can then form an ionic bond with a metal, such as Na, which will lose an electron (2 sodium atoms) to make Na2O (sodium oxide).

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Q: What happens to an atom of oxygen (O) when it forms an ionic bond in which it has the same electron configuration as the noble gas neon?
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What happens to an atom of fluorine when it forms an ionic bond in which it has the same electron configuration as the noble gas neon?

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