Oxygen, in its ground state, has 6 electrons in its outer most shell. In order to be like a noble gas, it needs 2 more, so it will gain 2 electrons to be O^2-. It can then form an ionic bond with a metal, such as Na, which will lose an electron (2 sodium atoms) to make Na2O (sodium oxide).
It accepts one electron.
The ions of elements nitrogen (N3-), oxygen (O2-), and fluorine (F-) will have the same electron configuration as a sodium ion (Na+), which is the same as the electron configuration of the noble gas neon.
study island answer- It gives up two electrons
Argon
A fluorine atom gains one atom in order to achieve the same electron configuration as neon. In doing so, the fluorine atom forms a fluoride ion with a 1- charge with the formula F-. As a negatively charged ion, it can form ionic bonds with various positively charged ions.
It accepts one electron.
It accepts one electron.
It accepts one electron.
The ions of elements nitrogen (N3-), oxygen (O2-), and fluorine (F-) will have the same electron configuration as a sodium ion (Na+), which is the same as the electron configuration of the noble gas neon.
study island answer- It gives up two electrons
Argon
A fluorine atom gains one atom in order to achieve the same electron configuration as neon. In doing so, the fluorine atom forms a fluoride ion with a 1- charge with the formula F-. As a negatively charged ion, it can form ionic bonds with various positively charged ions.
Adding one electron gives the chloride ion which has an octet (it achieves the same electron configuration as argon.
Oxygen
Alkali metals and alkaline earth metals will form ions (by losing 1 and 2 electrons respectively) with noble gas electron configuration.
Rhodium (Rh) forms a 3 plus ion that has the electron configuration Kr4d6. Rhodium has oxidation states of 2,3 and 4, so it can loan out 2, 3 or 4 electrons depending on the circumstances of a chemical reaction.
Chlorine (Cl)