That depends on actual circuit impedances and without knowing them cannot be answered in any way. But if all the circuit impedances are purely resistive, there will be no change in current flow with any change in frequency.
You must be talking about an inductive circuit. Impedance is inversely related to frequency with an inductor.
When the frequency of Parallel RL Circuit Increases,XL increases which causes IL (current through inductor) decreases. Decrease in IL causes It (It=Il+Ir) to decrease,which means by relation IT=Vs/Zt ,the Zt (Total Impedance) Increases.
A: the gain will be maximum at the open loop configuration and decrease as frequency increases
Inductor impedance is given by jwL, where w=2*pi*frequency. Therefore as the frequency increases the impedance of the inductor increases, causing a larger current flow and a larger power dissipation across the inductor
If resistance increases and voltage stays the same, then current decreases. Ohm's Law: Current equals Voltage divided by Resistance.
At resonance, the L and C impedance cancels out, so the current can be calculated based on the resistance and applied voltage. Imagine increasing frequency of the supply from 0 Hz to very high. At low frequency, the impedance of the inductor is ~0 (defined as Zl = w*L*j), and the impedance of the capacitor is very large (defined as Zc = 1 / (w*C*j)). As you increase the frequency, the impedance of the capacitor will decrease, as the impedance of the inductor increases. At some point (the resonant frequency), these two will be equal, with opposite signs. After crossing the resonant frequency, the inductor impedance will continue growing larger than the capacitor impedance until the total impedance approaches infinite.
Increase decrease. The frequency MUST decrease.
When the frequency of Parallel RL Circuit Increases,XL increases which causes IL (current through inductor) decreases. Decrease in IL causes It (It=Il+Ir) to decrease,which means by relation IT=Vs/Zt ,the Zt (Total Impedance) Increases.
Capacitive reactance (expressed in ohms) is inversely-proportional to the supply frequency, so it will decrease when the frequency increases. The following equation applies:XC = 1/(2 pi f C)where:XC = capacitive reactance, in ohmsf = frequency, in hertzC = capacitance, in farads
Frequency and energy decrease as wavelength increases.
decreases
If you're talking about an electric motor, increasing the frequency will increase the speed of rotation of the motor, and decreasing the frequency will decrease the speed of rotation of the motor. The other way of controlling a motor is to control the current; increasing the current increases speed, decreasing current decreases speed.
period
if the speed increases the frequency increases if the speed decrease the frequency decreases
when the frequency is increased the total impedance of a series RC circuit is decrease.
As a wavelength increases in size, its frequency and energy (E) decrease.
decreases
Dear Friend, we can observe over speed when frequency is increase in alternating current ANSWER: You will see that the time between peaks will shorten up. If rectified the amount of capacitance to reduce ripple will decrease.