it should become dimmer
If you add a second resistor, the resistance of series circuit will increase.
the current in series will be same..
The brightness of each bulb in a parallel circuit is the same as the brightness of a bulb in a simple circuit. By Kirchoff's voltage law, each element of a parallel circuit has the same voltage drop across it. With the same voltage, the same type of bulb will dissipate the same power, and have the same brightness.
The whole circuit fails - because the action of the bulb blowing cuts the circuit.
it increases
u see the light bulbs on a series circuit's brightness evolves and the brightness on a parallel's circuit dont
If you add a second resistor, the resistance of series circuit will increase.
It depends what is the outcome of burning. If that light has created open circuit, circuit will break and there will not be any current. But if there is short circuit means overall resistance is decreased. Thus current will increase. Besides overall brightness will also increase. Thus, if in a series lesser the number of bulbs more will be brightness.
ANSWER: The brightness of both bulbs will decrease. If the bulbs are identical the current will decrease to 0.2 Amps. This is a simple series resistive circuit, the more bulbs you add in series both the amperage and bulb brightness will continue to go down.
Nothing. That's why it's a parallel circuit. If it was a series circuit, then the first bulb would go out.
Unscrewing any bulb in a series circuit turns them all off. This is the same as opening the switch that controls them.
As a series circuit, as asked, all bulbs will go off because of that just one bulb.
The brightness would remain constant but the power draw will increase. If the circuit was series wired, the brightness would go down as you added bulbs.
If they have the same resistance they will. Kirchhoff's' Law.
The series circuit becomes an open circuit because there is no remaining path.
the current in series will be same..
The brightness of each bulb in a parallel circuit is the same as the brightness of a bulb in a simple circuit. By Kirchoff's voltage law, each element of a parallel circuit has the same voltage drop across it. With the same voltage, the same type of bulb will dissipate the same power, and have the same brightness.