it increases
If you keep all of them in series, then each component in your circuit will have more voltage across it and more current through it, and will dissipate more power (heat). If you keep all of the batteries in parallel, then they must all be rated for the same voltage. Nothing about the circuit's performance will change, but it'll be able to operate longer before the batteries die.
the current in series will be same..
As more light bulbs are added in a series circuit, the effective resistance of the circuit increases. That causes the current leaving the source to decrease.
Voltage attempts to make a current flow, and current will flow if the circuit is complete. It is possible to have voltage without current, but current cannot flow without voltage. The answer is "yes",voltage remains the same as current moves through the circuit.As the voltage remains constant, current increases in the circuit.
A voltage error circuit is called an error amplifier and happens when there are discrepancies between the voltage output and the reference voltage. A current error circuit happens when there is a disruption of flow in an ammeter.
it increases
the voltage and current doubles
Depends on how you add them. Added in series, the voltage will increase, maybe to the point of damaging the LED. If the LED survives, it will shine brighter. Added in parallell, the LED will shine the same, and will be able to shine longer before draining the batteries.
If resistance is increased, current decreases. Ohm's Law: current equals voltage divided by resistance.
If you don't change the voltage between the ends of the circuit,then higher resistance in the circuit means lower current (amps).
If you keep all of them in series, then each component in your circuit will have more voltage across it and more current through it, and will dissipate more power (heat). If you keep all of the batteries in parallel, then they must all be rated for the same voltage. Nothing about the circuit's performance will change, but it'll be able to operate longer before the batteries die.
The power in the circuit will increase.
It depends what is the outcome of burning. If that light has created open circuit, circuit will break and there will not be any current. But if there is short circuit means overall resistance is decreased. Thus current will increase. Besides overall brightness will also increase. Thus, if in a series lesser the number of bulbs more will be brightness.
current is decreased Depends of the circuit or device: in a stepdown transformer: power in= power out, V x I = V x I , Increase voltage in (power remaining constant) you current output will increase.
when the frequency is increased the total impedance of a series RC circuit is decrease.
If the batteries have EXACTLY the same voltage, then nothing will happen, because there will be no voltage drop in the circuit, and hence no current. If the batteries have SLIGHTLY different voltages, then there will be a voltage drop in the circuit. Since there is low resistance, there might be high current, causing damage and/or an explosion. In all probability, however, there is enough internal resistance in the batteries to simply cause them to equalize in voltage.
the current in series will be same..