If the wiring is in series, the entire circuit is cut and the current is zero. If the wiring is in parallel, the current decreases. I'm too occupied to write out formulas and examples on hypothetical scenerios, but the current decreases with lessened loads. C'mon! You didn't know that??...
All the other lamps will go out, and the full supply voltage will appear across the empty lamp holder.
The bulb will cease to glow, and will eventually cool off.
You know if current is flowing in a bulb circuit because, if there is enough power (voltage times current), the bulb will illuminate. If there is current, but not enough power to illuminate the bulb, you will need to measure the current with an ammeter to see if there is any current.
Answer: it will burn out **Explain:**The same current flows through each part of a series circuit. If the circuit is broken at any point there won't be any current that will flow. In this case, if one of the bulbs blew out, the other bulb would not be able to light up because the flow of electric current would have been interrupted. #Carryonlearning
A series circuit is where there is only one path for the current. As a result, and as a direct consequence of Kirchoff's current law, the current at every point in a series circuit is the same. The two bulbs have the same current flowing through them.
If the bulb is of the incandescent variety, then reducing the current in the circuit will do this.
The whole circuit fails - because the action of the bulb blowing cuts the circuit.
If you unscrewed any bulb in the circuit it would turn all of the bulbs off.
The circuit will have the flow of electricity interrupted.
Possibly. If it still works when you turn it on, the of course it is using power. If it does not work when it otherwise would, then it is definitely not using power, just as if you didn't have the bulb there at all. <<>> With the voltage on the circuit and the light bulb in the circuit, the bulb will glow. If you unscrew the bulb until it goes out the potential voltage will still be in the circuit but no current will flow so no power will be used. In this scenario the unscrewing of the bulb will be the same as using a switch in the circuit to interrupt the current flow.
The resistance is increased, the voltage across each bulb is decreased and the current through the circuit is reduced.
The failed bulb breaks the circuit so no current can flow - so the other bulb goes out (but is OK).
current in series always stays the same
You know if current is flowing in a bulb circuit because, if there is enough power (voltage times current), the bulb will illuminate. If there is current, but not enough power to illuminate the bulb, you will need to measure the current with an ammeter to see if there is any current.
If one bulb in a series circuit goes out, then current can't flow anywherein the circuit. A circuit in which current can't flow is an open circuit.
Answer: it will burn out **Explain:**The same current flows through each part of a series circuit. If the circuit is broken at any point there won't be any current that will flow. In this case, if one of the bulbs blew out, the other bulb would not be able to light up because the flow of electric current would have been interrupted. #Carryonlearning
A series circuit is where there is only one path for the current. As a result, and as a direct consequence of Kirchoff's current law, the current at every point in a series circuit is the same. The two bulbs have the same current flowing through them.
A switch is used of stop the current flow in a circuit and the bulb can be classed as the load in a circuit.
The bulb will get brighter