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What happens to the force between the charges when the separation distance is tripled?
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What happens to the force between two charges if the magnitude of both charges is doubled and the distance between them is cut in half?
The force between the two charges increases 16 times.Coulomb's law equation states:│F│ = ke │q1q2│/r2Where (F) is the force acting simultaneously on both point charges (q1) and (q2).r is the separation distance and ke is a proportionality constant called the Coulombconstant.Using above equation, if we double both charges and reduce the distance in half.│F2│ = ke │(2q12q2)│/(r/2)2 = 16 ke │q1q2│/r2 = 16 │F│.We see that the force turns out 16 times stronger
What happens to the electric force between two charges if you increase the distance between them by a factor of 5?
Since you are reducing the distance between the charges by 7 times, hence the new force b/w the charges will be 49 times the electric force between the charges in the previous condition.
What happens to the electrostatic force if one charge is quadupled?
If one of a pair of charges is quadrupled and the distance between them doesn't change, then the electrostatic force between them is also quadrupled.
If the distance is increased while the charges remain the same what happens to the force?
The force will decrease as the distance increases.
What happens to the force between charged and uncharged objects as the distance between them increased?
as the distance is increased statically induced charge in the uncharged object reduced to a minimum. Thus coulombic force which is directly proportional to the product of the charges tends to 0.
What happens to the distance interference fringes if the separation between the slits is increased?
decreases
What happens to the force between two charges if the magnitude of both charges is doubled and the distance between them is cut in half?
The force between the two charges increases 16 times.Coulomb's law equation states:│F│ = ke │q1q2│/r2Where (F) is the force acting simultaneously on both point charges (q1) and (q2).r is the separation distance and ke is a proportionality constant called the Coulombconstant.Using above equation, if we double both charges and reduce the distance in half.│F2│ = ke │(2q12q2)│/(r/2)2 = 16 ke │q1q2│/r2 = 16 │F│.We see that the force turns out 16 times stronger
What happens to the electric force between two charges if you increase the distance between them by a factor of 5?
Since you are reducing the distance between the charges by 7 times, hence the new force b/w the charges will be 49 times the electric force between the charges in the previous condition.
What happens to the electrostatic force if one charge is quadupled?
If one of a pair of charges is quadrupled and the distance between them doesn't change, then the electrostatic force between them is also quadrupled.
If the distance is increased while the charges remain the same what happens to the force?
The force will decrease as the distance increases.
What happens to the force between charged and uncharged objects as the distance between them increased?
as the distance is increased statically induced charge in the uncharged object reduced to a minimum. Thus coulombic force which is directly proportional to the product of the charges tends to 0.
What happens to the force between to objects being accelerated toward each other by gravitational attraction?
If the distance between them is decreasing, then the mutual gravitational attraction is increasing. They don't necessarily have to be accelerating. Just moving steadily would do it, as long as the separation distance is decreasing.
What happens when two positive charges repel?
Think about what happens when two magnets with a north pole are brought together. Ig becomes harder and harder to bring them together as the distance between them decrease. The last inch seems impossible no matter how hard you try. That's what happens when positive charges are brought together.
What happens to the force exerted between charged and uncharged objects as the distance increases between them?
As the distance is increased, statically induced charge in the uncharged object is reduced to a minimum. Thus coulombic force which is directly proportional to the product of the charges tends to 0
What happens to the force between two objects being accelerated toward each other by gravitational attraction?
If the distance between them is decreasing, then the mutual gravitational attraction is increasing. They don't necessarily have to be accelerating. Just moving steadily would do it, as long as the separation distance is decreasing.
What happens to the force between two charges if the magnitude of both charges is doubled and the distance between is doubled?
Force of attraction between charges is directly proportional to the charge. So as we quadrule each charge then force will become 4x4 ie 16 times increased Force is also inversely related to the square of the distance. So as we double the distance then the force is decreased by 22 ie 4 times Hence the net change will be 16/4 ie 4 times increase in the force of attraction.
Two charges are separated by a distance d If one the charges is doubled while the other is tripled what happens to the force between the charges?
We have to assume that the distance between the charges remains constant, and the answer doesn't depend on the distance. The force between the charges is proportional to the product of the charges. Initial force = constant x (Q1) x (Q2) New force = constant x (2Q1) x (3Q2) = 6 x (Q1) x (Q2) = 6 times the initial force. The direction of the force doesn't change. It's attractive if the charges are of opposite sign, repulsive if they're of like sign.
